Question

Someone pls pls help ​

Answer 1

Answer:

4√2 cm

Step-by-step explanation:

ABCD is a square.

Each side measures 8 cm.

So,

AB = BC = CD = AD = 8 cm

P, Q, R, and S are mid - points of ABCD.

P is the mid - point of AB.

So,

AP = PB

AP + PB = AB

AP + AP = AB

2AP = 8

AP = 8 / 2

AP = 4 cm

S id the mid - point of AD.

So,

DS = SA

DS + SA = AD

SA + SA = AD

2SA = 8

SA = 8 / 2

SA = 4 cm

Property of a square : The angle between two sides is 90°.

So,

The angle between side SA and AP is 90°.

So,

SA, AP and SP forms a right angled triangles.

By Pythagoras theorem,

( SP)² = ( SA )² + ( AP )²

( SP )² = 4² + 4²

= 16 + 16

( SP )² = 32

SP = √32

SP = 4√2 cm

Since PQRS is also a square.

In square, all sides are equal.

So,

PQ = QR = RS = SP

Since SP = 4√2 cm

Hence,

PQ = 4√2 cm

Therefore,

the length of PQ is 4√2 cm.

Answer 2

Answer: 5.7

Step-by-step explanation:

Midpoint means the middle of line. So to find the middle of the line I just need to divide the line by 2.

So the midpoint of AB is:

8/2=4 = BP

Since Q is also a midpoint so BQ is equal to 4.

We know BP=BQ=4. Looking at the diagram we can tell PBQ is a triangle.

The hypotenuse of the triangle is PQ.

Pythagoras's theorem helps us to find the hypotenuse. So we just plug in the values to find PQ.

P's Theorem : a²+b²=c²

basically in the case of this question it means:

(BP)²+(BQ)²=(PQ)²

now we just subsiture the values and solve for PQ:

4²+4²=(PQ)²

16+16=(PQ)²

32=(PQ)²

PQ=5.65...

= 5.7(rounded to one decimal place)