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slega [8]
2 years ago
10

(2 * 10^-2) +(9*10^-3) Please before Wednesday

Mathematics
2 answers:
krek1111 [17]2 years ago
4 0

Answer:

0.029

Step-by-step explanation:

2*10^-2 = 0.02

9*10^-3 = 0.009

0.02 + 0.003 = 0.029

anzhelika [568]2 years ago
3 0

Answer:

try symnolab it helps a lot with math but the answer is 29/1000 0r 0.029

Step-by-step explanation: Hopes this helps :)

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The distance will be multiplied by t, so is ...

  |w-v| = (√11)t

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The difference between two integers is 8 and their product is 65. Assume that the larger of the two numbers is x. Write a quadra
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A quadratic equation in standard form that can be used to determine the value of x is x^{2} - 8x - 65 = 0.

The Factor of the equation from Part B is (x - 13)(x + 5)  and the possible solutions to the equation is x = 13 or -5.

The value for the second number is 5

<h3>Word Problem Leading To Quadratic Equation.</h3>

The general formula for quadratic equation in a in standard form is

ax^{2} + bx + c = 0

Given that the  difference between two integers is 8

Let the two integers = x and y,

and their product is 65. If the larger of the two numbers is x. Then,

x - y = 8 and xy = 65

Since we are looking for the value of x, make y the subject of formula in the first equation.

y = x - 8

Substitute y in the second equation.

x(x - 8) = 65

x^{2} - 8x - 65 = 0

x^{2} - 13x + 5x - 65 = 0

(x - 13)(x + 5) = 0

x = 13 or -5

We will ignore -5 since x is the larger number.

To get y Substitute x in the second equation.

xy = 65

13y = 65

y = 65/13

y = 5

Therefore, a quadratic equation in standard form that can be used to determine the value of x is x^{2} - 8x - 65 = 0. The Factor of the equation from Part B is (x - 13)(x + 5)  and the possible solutions to the equation is x = 13 or -5. The value for the second number is 5

Learn more about Quadratic Equation here: brainly.com/question/25841119

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