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2 years ago

In a teacher's math course, a linear regression line was calculated to predict

Mathematics

1 answer:

Marat540 [252]2 years ago

6 0

The given equation is the best line that approximates the linear

relationship between the midterm score and the score in the final exam.

AJ's residual is 0.3, which is not among the given options, therefore, the correct option is. <u>E. None of these</u>.

Reasons:

The given linear regression line equation is; $\hat y$ = 25.5 + 0.82· $\mathbf{\hat x}$

Where;

$\hat y$ = Final exam score;

$\hat x$ = The midterm score;

AJ score in the first test, $\hat x$ = 90

AJ's actual score in the exam = 99

Required:

The value of AJ's residual

Solution:

By using the regression line equation, we have;

The predicted exam score, $\hat y$ = 25.5 + 0.82 × 90 = 99.3

The residual score = Predicted score - Actual score

∴ AJ's residual = 99.3 - 99 = 0.3

AJ's residual = 0.3

Therefore, the correct option is option E;

<u>E. None of these</u>

Learn more about regression line equation here:

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Akimi4 [234]

Answer:

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Thus, option A) is true.

The solution to the system of equations be:

$x = 4, y = 5$

Step-by-step explanation:

It is important to remember that when we solve the system of equations, the first step we need to do is to solve one of the equations for one of the variables.

Given the system of equations

$x - y = -1$

$2x - y = 3$

Step 1: Solve one of the equations for one of the variables. Let's solve the first equation for x

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Add y to both sides

$x-y+y=-1+y$

$x=-1+y$

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<u>NOW LET US SOLVE THE REMAINING PORTION</u>

$\mathrm{Subsititute\:}x=-1+y$ to solve for y

$\begin{bmatrix}2\left(-1+y\right)-y=3\end{bmatrix}$

$-2+y=3$

$y=5$

For x = -1 + y

substitute y = 5

$x=-1+5$

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Thus, the solution to the system of equations be:

$x = 4, y = 5$

3 0

2 years ago

Moira said, "If a right triangle has one side with a length of 3 units and one side with a length

Dima020 [189]

If the two sides with length 3 and 4 are the two legs, then the missing side, i.e. the hypotenuse, is indeed 5.

But it could also be the case that 4 is the hypotenuse and 3 is one of the legs. In this case, the missing side is the other leg, so we calculate it using

$\sqrt{4^2-3^2}=\sqrt{16-9}=\sqrt{7}$

So, a right triangle with legs $\sqrt{7}$ and 3 has an hypotenuse of 4.

8 0

3 years ago

(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ

quester [9]

Answer:

Step-by-step explanation:

Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.

On expanding the left hand side of the expression we have;

= (8x² −15x)−(x² −27x)

Open the paranthesis

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collect the like terms

= 8x²−x²+27x −15x

= 7x²+12x

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2 years ago

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3 years ago

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Answer:

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