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2 years ago

Please answer this ASAP

Mathematics

1 answer:

valkas [14]2 years ago

6 0

Answer:

x = 2

Step-by-step explanation:

First, let's write out our equation:

$2x-4=6-3x$

I want to isolate x on one side, so first, I'll add 4 to both sides to remove the -4 from next to 2x:

$2x-4+4=6-3x+4\\2x=-3x + 10$

Notice that I combined like terms with the -4 and 4 (to get 0) and the 6 and 4 on the right side (to get 10). Next, I'll add 3x to both sides:

$2x + 3x = -3x + 3x + 10$

And then I'll add like terms:

$5x=10$

Now, all we have to do is divide both sides by 5:

$5x/5=10/5\\x=2$

And there's our answer. Hopefully that's helpful! :)

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if a sequence is defined recursively by f(0)=4 and f(n+1)= -3f(n+1)=-3f(n)+1 for n≥0, then f(3) is equal to? DESPERATELY NEED HE

muminat

f(3) is equal to -101.

<u>Step-by-step explanation</u>:

The sequence is followed by f(0)=4
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Put n=0,

f(0+1)= -3f(0)+1

f(1)= -3(4)+1

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f(3)= -3(34)+1

f(3)= -102+1

f(3)= -101

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If an<br> angle has a measure of 43°, what is the<br> measure of its complement?

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If a point P(x,y) is the equidistant from the points A(2,3) and B(6,1), find the equation of locus of moving point P.

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Answer:

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Step-by-step explanation:

A locus can be defined as a curve or figure formed by all the points satisfying a particular equation of the relation between coordinates.

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The distance d1 from (x,y) to (2,3) is:

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Since d1=d2:

$\sqrt{(x-2)^2+(y-3)^2}=\sqrt{(x-6)^2+(y-1)^2}$

Squaring both sides:

$(x-2)^2+(y-3)^2=(x-6)^2+(y-1)^2$

Operating:

$x^2-4x+4+y^2-6y+9=x^2-12x+36+y^2-2y+1$

Simplifying all the squares:

$-4x+4x+4-6y+9=-12x+36-2y+1$

Moving the variables to the left side and the numbers to the right side:

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