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borishaifa [10]

3 years ago

6

Simplify

atex-formula">

2 answers:

blondinia [14]3 years ago

7 0

The answer is in the picture below .

Scilla [17]3 years ago

7 0

1/y3 hope this helps

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Manny bought a brand new car in 2012 for $28,750. If the car depreciates by 12% each year, write an exponential function to mode

patriot [66]

The exponential formula for this situtation will be given by:
f(x)=ae^(-bx)
where:
a=initial price
b=rate
x=time in years
hence the formula will be:
f(x)=28750e^(-0.12x)
thus the value of the car in 2018 will be:
x=2018-2012=6 years
thus
f(6)=28750e^(-0.12*6)
f(6)=$13,994.13

5 0

3 years ago

What is the area of a square when the length is 6 inches.?

Montano1993 [528]

Area = Length x Width
On a square, the length and width are both equal (6 inches)

Substitute the 6 in for length and width
Area = 6 x 6

Answer:
Area = 36

8 0

3 years ago

Write a ratio for each phrase :<br> 5 cupcakes for every 2 children

Pani-rosa [81]

5/2
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3 0

3 years ago

What is 5.43 didided by 15

Nookie1986 [14]

Divided

5.43÷15=0.362

5 0

4 years ago

Read 2 more answers

Kristen lives directly east of the park. The football field is directly south of the park. The library sits on the line formed b

klemol [59]

Imagine right triangle PHF, where P - park, H - home and F - football field, then PH, PF are legs and HF is hypotenuse . Denote point L to be library. You know that point L lies on the segment FH and FL=8, LH=2. Also you know that PL is an altitude to the hypotenuse.

Use the property of altitude drawn from the vertex of right angle to the hypotenuse (the length of the altitude is geometrical mean between legs' projections onto hypotenuse):

$PL=\sqrt{HL\cdot LF},\\ PL=\sqrt{2\cdot 8}=\sqrt{16} =4$ mi.

This means that the distance between park and libriry is 4 miles.

Consider right triangle PLF ( angle L is right angle and PF - hypotenuse). By the Pythagorean theorem,

$PF^2=PL^2+LF^2,\\ PF^2=4^2+8^2,\\ PF^2=16+64=80,\\ PF=\sqrt{80} =4\sqrt{5}$ mi. The distance between park and football field is $4\sqrt{5}$ miles.

Answer: the distance between park and libriry is 4 miles and the distance between park and football field is $4\sqrt{5}$ miles.

6 0

3 years ago