Answer:
Answer: E
Helen, a high school teacher, wants her students to actively participate more in class. She has decided to use reinforcement theory to get the required results. Which of the following methods is she most likely to use?
.a) She is going to call on students who never participate
.b) She is going to yell at students, telling them that they are not making good grades
.c) She is going to ask the students that always participate to allow the others to have a chance
.d) She is going to model what active participation should look like ,at the beginning of class
.e) She is going to give students extra credit each time that they contribute.
By using the given ratio, we will see that the diagonal measures 50 inches.
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How to get the diagonal of the screen?</h3>
First, we know that the ratio between length and width is 16:9, and the length is 43.6 inches, then the width will be:
W = (9/16)*43.6 inches = 24.5 in
Now, the diagonal will be equal to the hypotenuse of a right triangle with catheti of 43.6 in and 24.5 in, by using Pythagorean's theorem we get:

We conclude that the diagonal measures 50 inches.
If you want to learn more about ratios:
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True. A nuclear family includes a couple and their dependent children. Now a days there are many types of families like single parent families, extended families, childless families, step families, etc.
Answer:
a marketable service
Explanation:
that should be the answer
The point slope form of the asymptote of the hyperbola is; y - 4 = ±(6/7)(x - 6)
- We are given the equation of the hyperbola as;
[(y + 4)²/36] - [(x - 6)²/49] = 1
- We can rewrite this equation as;
[(y + 1)²/6²] - [(x - 6)²/7²] = 1
- The general equation form of hyperbola is;
[(y - k)²/a²] - [(x - h)²/b²] = 1
- Comparing this general form to our given equation we can see that;
k = -4
h = 6
a = 6
b = 7
- Now the equation of the asymptote of a hyperbola follows the general formula;
y = ±[a(x - h)/b] + k
- Plugging in the relevant values gives us;
y = ±(6/7)(x - 6) - 4
>> y - 4 = ±(6/7)(x - 6)
Read more about hyperbola asymptotes at; brainly.com/question/12919612