Expand the expression?

Perform indicated multiplication:

7a(2a)+7a(-5)-4(2a)-4(-5)

14a^2-35a-8a+20 combine like terms, ie (-35a-8a)=-43a

14a^2-43a+20

5 0

2 years ago

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Which category is not one of the major responsibilities of state government?

just olya [345]

Answer: C electricity

Step-by-step explanation:

It is

4 0

2 years ago

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Solve the x <br> 1/3x + 5> 10

kotykmax [81]

Answer:

The solution to the inequality is:

$\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}$

The solution graph is also attached below.

Step-by-step explanation:

Given

We are given the expression

$\frac{1}{3}x+5>10$

To determine

Solve for x

Given the expression

$\frac{1}{3}x+5>10$

Subtract 5 from both sides

$\frac{1}{3}x+5-5>10-5$

Simplify

$\frac{1}{3}x>5$

Multiply both sides by 3

$3\cdot \frac{1}{3}x>5\cdot \:3$

Simplify

$x>15$

Thus, we conclude that:

$x>15$

Therefore, the solution to the inequality is:

$\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}$

The solution graph is also attached below.

5 0

2 years ago

A certain large manufacturing facility produces 20,000 parts each week. The manager of the facility estimates that about 1% of t

Slav-nsk [51]

Answer:

198 is the variance for the number of defective parts made each week.

Step-by-step explanation:

We are given the following in the question:

Number of parts produced each week = 20,000

Percentage of defective parts = 1%

We have to calculate the variance for the number of defective parts made each week.

We treat defective part as a success.

P(Defective part) = 1% = 0.01

$p = 0.01$

Then the number defective parts follows a binomial distribution .

Formula for variance =

$\sigma^2 = np(1-p) = 20000(0.01)(1-0.01) = 198$

Thus, 198 is the variance for the number of defective parts made each week.

8 0

3 years ago