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3 years ago

13

3/4 + 3/4 in simplset form

2 answers:

dalvyx [7]3 years ago

5 0

Answer:

6/4 or 3/2

Step-by-step explanation:

nirvana33 [79]3 years ago

4 0

Answer:

The answer should be 3/2

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Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

4 0

3 years ago

Quadrilateral ABCD is plotted with coordinates A(3,7), B(6,1), C(-6,-8) and D(-5,1). Using coordinate geometry, prove that ABCD

tiny-mole [99]

Answer:

Step-by-step explanation:

4 0

2 years ago

How to solve -2 = -6 + 4v?

liq [111]

Hello there.

<span>How to solve -2 = -6 + 4v?</span>
<span><span>−2</span>=<span><span>4v</span>−6</span></span>
<span><span><span>4v</span>−6</span>=<span>−2</span></span>
<span><span><span><span>4v</span>−6</span>+6</span>=<span><span>−2</span>+6</span></span><span><span>4v</span>=4</span>
<span><span><span>4v/</span>4</span>=<span>4/4
</span></span><span>v=1</span>

3 0

3 years ago

Read 2 more answers

The potential energy, P, in a spring is represented using the formula P = P equals StartFraction one-half EndFraction k x square

Anastaziya [24]

Answer:

$k=\frac{2P}{x^{2}}$

Step-by-step explanation:

<u><em>The question is</em></u>

Which equation should she use?

we have the formula

$P=\frac{1}{2}kx^{2}$

Solve for k

That means ----> isolate the variable k

Multiply by 2 both sides

$2P=kx^{2}$

Divide by x^2 both sides

$\frac{2P}{x^{2}}=k$

Rewrite

$k=\frac{2P}{x^{2}}$

6 0

3 years ago

If k = p+2q/3 , find the value of p when k=7 and q=3

marishachu [46]

Answer:

p = 5

Step-by-step explanation:

hopefully it is clear and understandable :)

6 0

3 years ago