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Vanyuwa [196]
2 years ago
9

1. (01.03 MC) What is a string in Python

Computers and Technology
2 answers:
luda_lava [24]2 years ago
7 0

Answer:

sorry I haven't answer your question but please can you provide me the information about the computer python

hoa [83]2 years ago
5 0

Answer:

a or b

Explanation:

hope it help bye thank you

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Describe the impact of improvement ls in technology and transportation on american citizens. ​
EastWind [94]

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How did technology affect the growth of cities and housing within them? ... Advances in technology and greater business efficiency and productivity further expanded the variety of goods and services within their reach. The growing middle class also supported an expansion of higher education.

Explanation:

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2 years ago
Which of the following declares an abstract method in an abstract C++ class? (Points : 2) public: void print();
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Answer:

public: virtual void print()=0;

Explanation:

An abstract class contains a pure virtual function. Pure virtual class cannot be instantiated but it can be subclassed and the subclass can provide an implementation of the function.

A virtual function declaration in the class is preceded by the virtual keyword. For example, virtual void print();

A pure virtual function declaration is followed by '=0;'

public: virtual void print()=0;

4 0
3 years ago
Carlos owns a hardware store. He currently is not using any software to track what he has in the store. In 1–2 sentences, descri
Tresset [83]

Carlos Should use a Security Camera to keep track of his physical hardware. Carlos can then use a computer to monitor the security cameras.

7 0
3 years ago
Read 2 more answers
A testing lab wishes to test two experimental brans of outdoor pain long each wiil last befor fading . The testing lab makes six
Simora [160]

Answer:

The answer is "\bold{Brand \ A \ (35, 350, 18.7) \ \ Brand \ B \ (35, 50, 7.07)}"

Explanation:

Calculating the mean for brand A:

\to \bar{X_{A}}=\frac{10+60+50+30+40+20}{6}  =\frac{210}{6}=35

Calculating the Variance for brand A:

\sigma_{A}^{2}=\frac{\left ( 10-35 \right )^{2}+\left ( 60-35 \right )^{2}+\left ( 50-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 20-35 \right )^{2}}{5} \\\\

     =\frac{\left ( -25 \right )^{2}+\left ( 25  \right )^{2}+\left ( 15\right )^{2}+\left ( -5 \right )^{2}+\left ( 5 \right )^{2}+\left ( 15 \right )^{2}}{5} \\\\ =\frac{625+ 625+225+25+25+225}{5} \\\\ =\frac{1750}{50}\\\\=350

Calculating the Standard deviation:

\sigma _{A}=\sqrt{\sigma _{A}^{2}}=18.7

Calculating the Mean for brand B:

\bar{X_{B}}=\frac{35+45+30+35+40+25}{6}=\frac{210}{6}=35

Calculating the Variance for brand B:

\sigma_{B} ^{2}=\frac{\left ( 35-35 \right )^{2}+\left ( 45-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 35-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 25-35 \right )^{2}}{5}

    =\frac{\left ( 0 \right )^{2}+\left ( 10 \right )^{2}+\left ( -5 \right )^{2}+\left (0 \right )^{2}+\left ( 5 \right )^{2}+\left ( -10 \right )^{2}}{5}\\\\=\frac{0+100+25+0+25+100}{5}\\\\=\frac{100+25+25+100}{5}\\\\=\frac{250}{5}\\\\=50

 Calculating the Standard deviation:  

\sigma _{B}=\sqrt{\sigma _{B}^{2}}=7.07

4 0
3 years ago
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