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2 years ago

9

T

1 answer:

weqwewe [10]2 years ago

4 0

Answer:

28

Step-by-step explanation:

140 - 56 = 84 bottles

5 - 2 = 3 minutes

84 / 3 = 28 bottles per minute

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If the image below is dilated with a scale factor of 2, what is the perimeter of the dilated image?

garri49 [273]

Answer:

the answer is 24

Step-by-step explanation:

i got it correct on my test

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2 years ago

What are the solutions to the system of equations? y=−x^2−5x−6 x+y=−3

Dmitriy789 [7]

Answer:

The solutions are the points (-3,0) and (-1,-2)

Step-by-step explanation:

we have

$y=-x^{2} -5x-6$ -----> equation A

$x+y=-3$ -----> equation B

Solve the system of equations by graphing

The solution of the system of equations are the intersection points both graphs

The solutions are the points (-3,0) and (-1,-2)

see the attached figure

5 0

3 years ago

How many eights are there in 6 1/2

Alona [7]

There are (8) eighths in 1, so multiply this by 6 1/2 to determine how many eighths there are:

8*6.5 = <u><em>52 eighths</em></u> in 6 1/2

5 0

3 years ago

Read 2 more answers

Given that the discriminant of a quadratic equation is 0, determine the number of real solutions.

Alisiya [41]

If the discrimination is equal to 0, there is one real solution

8 0

2 years ago

The line 3x-8y=k cuts the x-axis and y- axis at the point A and B respectively. If the area of ∆AOB =12sq.units, find the value

Sladkaya [172]

Given:

The equation is:

$3x-8y=k$

It cuts the x-axis and y- axis at the point A and B respectively.

The area of ∆AOB =12 sq.units.

To find:

The value of <em>k</em>.

Solution:

We have,

$3x-8y=k$

Substituting $x=0$ to find the y-intercept.

$3(0)-8y=k$

$0-8y=k$

$y=\dfrac{k}{-8}$

$y=-\dfrac{k}{8}$

Substituting $y=0$ to find the x-intercept.

$3x-8(0)=k$

$3x-0=k$

$x=\dfrac{k}{3}$

Area of a triangle is:

$A=\dfrac{1}{2}\times base\times height$

The height of the ∆AOB is $OB=\dfrac{k}{8}$ because distance cannot be negative and the base of the ∆AOB is $OA=\dfrac{k}{3}$ . So, the area of the ∆AOB is:

$A=\dfrac{1}{2}\times \dfrac{k}{8}\times \dfrac{k}{3}$

$A=\dfrac{k^2}{48}$

It is given that, the area of ∆AOB = 12 sq.units.

$\dfrac{k^2}{48}=12$

$k^2=576$

$k=\pm \sqrt{576}$

$k=\pm 24$

Therefore, the value of k is either 24 or -24.

4 0

2 years ago