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andrew-mc [135]
3 years ago
7

(6-i\sqrt(2))/(6+i\sqrt(2))

Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Answer: 18 sqrt= i

Hope this helps :)

Step-by-step explanation:

You might be interested in
6) Supplementary Exercise 5.51
tresset_1 [31]

Answer:

P(X \le 4) = 0.7373

P(x \le 15) = 0.0173

P(x > 20) = 0.4207

P(20\ge x \le 24)= 0.6129

P(x = 24) = 0.0236

P(x = 15) = 1.18\%

Step-by-step explanation:

Given

p = 80\% = 0.8

The question illustrates binomial distribution and will be solved using:

P(X = x) = ^nC_xp^x(1 - p)^{n-x}

Solving (a):

Given

n =5

Required

P(X\ge 4)

This is calculated using

P(X \le 4) = P(x = 4) +P(x=5)

This gives:

P(X \le 4) = ^5C_4 * (0.8)^4*(1 - 0.8)^{5-4} + ^5C_5*0.8^5*(1 - 0.8)^{5-5}

P(X \le 4) = 5 * (0.8)^4*(0.2)^1 + 1*0.8^5*(0.2)^0

P(X \le 4) = 0.4096 + 0.32768

P(X \le 4) = 0.73728

P(X \le 4) = 0.7373 --- approximated

Solving (b):

Given

n =25

i)

Required

P(X\le 15)

This is calculated as:

P(X\le 15) = 1 - P(x>15) --- Complement rule

P(x>15) = P(x=16) + P(x=17) + P(x =18) + P(x = 19) + P(x = 20) + P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)

P(x > 15) = {25}^C_{16} * p^{16}*(1-p)^{25-16} +{25}^C_{17} * p^{17}*(1-p)^{25-17} +{25}^C_{18} * p^{18}*(1-p)^{25-18} +{25}^C_{19} * p^{19}*(1-p)^{25-19} +{25}^C_{20} * p^{20}*(1-p)^{25-20} +{25}^C_{21} * p^{21}*(1-p)^{25-21} +{25}^C_{22} * p^{22}*(1-p)^{25-22} +{25}^C_{23} * p^{23}*(1-p)^{25-23} +{25}^C_{24} * p^{24}*(1-p)^{25-24} +{25}^C_{25} * p^{25}*(1-p)^{25-25}

P(x > 15) = 2042975 * 0.8^{16}*0.2^9 +1081575* 0.8^{17}*0.2^8 +480700 * 0.8^{18}*0.2^7 +177100 * 0.8^{19}*0.2^6 +53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0  

P(x > 15) = 0.98266813045

So:

P(X\le 15) = 1 - P(x>15)

P(x \le 15) = 1 - 0.98266813045

P(x \le 15) = 0.01733186955

P(x \le 15) = 0.0173

ii)

P(x>20)

This is calculated as:

P(x>20) = P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)

P(x > 20) = 12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0

P(x > 20) = 0.42067430925

P(x > 20) = 0.4207

iii)

P(20\ge x \le 24)

This is calculated as:

P(20\ge x \le 24) = P(x = 20) + P(x = 21) + P(x = 22) + P(x =23) + P(x = 24)

P(20\ge x \le 24)= 53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1

P(20\ge x \le 24)= 0.61291151859

P(20\ge x \le 24)= 0.6129

iv)

P(x = 24)

This is calculated as:

P(x = 24) = 25* 0.8^{24}*0.2^1

P(x = 24) = 0.0236

Solving (c):

P(x = 15)

This is calculated as:

P(x = 15) = {25}^C_{15} * 0.8^{15} * 0.2^{10}

P(x = 15) = 3268760 * 0.8^{15} * 0.2^{10}

P(x = 15) = 0.01177694905

P(x = 15) = 0.0118

Express as percentage

P(x = 15) = 1.18\%

The calculated probability (1.18%) is way less than the advocate's claim.

Hence, we do not believe the claim.

5 0
3 years ago
What is the answer? Will give brainilist.
Elina [12.6K]

Answer:

7

Step-by-step explanation:

first put them in order

5,6,6,8,9,9

now the ones that are in the middle are 6 and 8 so we find the  average by adding them then dividing by 2

6+8=14/2=7

5 0
3 years ago
An item is regularly priced at $85. It is now priced at a discount of 35% off the regular price.
Klio2033 [76]

Answer:

The price would be 55.25 in U.S dollars, you saved 29.75. $85 x .35=29.75.

5 0
4 years ago
Read 2 more answers
HELP ASAP
Serjik [45]

Answer:

8π units²

Step-by-step explanation:

center=((-1+3)/2,(-2+2)/2)=(1,0)

radius~r=\sqrt{(3-1)^2+(2-0)^2} =\sqrt{4+4} =\sqrt{8} \\area~of~circle=\pi r^2=\pi  \times (\sqrt{8} )^2=8\pi ~square~units.

6 0
4 years ago
What is the value of the expression when s=2 and t=1.5 -3|5-s3|+3t​
Anuta_ua [19.1K]

Answer:

-4.5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • |Absolute Value| - makes any negative number positive

Step-by-step explanation:

<u>Step 1: Define</u>

-3|5 - s³| + 3t

s = 2

t = 1.5

<u>Step 2: Evaluate</u>

  1. Substitute in variables:                                                                                     -3|5 - 2³| + 3(1.5)
  2. |Absolute Value| Exponents:                                                                            -3|5 - 8| + 3(1.5)
  3. |Absolute Value| Subtract:                                                                               -3|-3| + 3(1.5)
  4. Absolute Value:                                                                                                -3(3) + 3(1.5)
  5. Multiply:                                                                                                             -9 + 4.5
  6. Add:                                                                                                                   -4.5
6 0
3 years ago
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