<h3>
Answer:</h3>
PR ≈ 14.50
<h3>
Step-by-step explanation:</h3>
Since ∠Q is a right angle, the area can be found from ...
... A = (1/2)bh = (1/2)(QP)(PR)
From trigonometry, we know ...
... QP = PR·cos(P) = PR·cos(36°)
... QR - PR·sin(P) = PR·sin(36°)
Substituting these values and the given area into the area formula gives ...
... 50 = (1/2)(PR·cos(36°))(PR·sin(36°))
... 100/(sin(36°)cos(36°)) = (PR)²
... PR = 10/√(sin(36°)cos(36°))
... PR ≈ 14.5015
Since f(2) is not given in the function definition, you must use f(n) with n=2. That tells you
... f(2) = -29 -f(1)
Now, f(1) is defined, so use that value.
... f(2) = -29 -(-16) = -29 +16
... f(2) = -13
