Answer:
75.94% of the households spent between $5.00 and $9.00 on sugar.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What proportion of the households spent between $5.00 and $9.00 on sugar?
This is the pvalue of Z when X = 9 subtracted by the pvalue of Z when X = 5. So
X = 9
has a pvalue of 0.7611
X = 5
has a pvalue of 0.0017.
So 0.7611 - 0.0017 = 0.7594 = 75.94% of the households spent between $5.00 and $9.00 on sugar.
Answer:
true
Step-by-step explanation:
its TRUE :)
Question isn't well formatted ;
If the question meant that choosing a marble for five hundred times ; then the calculation is stated below:
Answer:
214
Step-by-step explanation:
Given that :
Probability of picking a red out of a bag of colored marble = 3 : 7 ; that is 3 / 7
P(red) = 3 / 7
If the number of picks (with replacement) = 500
Then, the approximate number of red marbles chosen will be :
P(red) * number of picks
3/7 * 500 = 214.285
Approximate Number of red marbles chosen = 214
Answer:
The 315 hours is the value of a: statistic
Step-by-step explanation:
A random sample of 650 power cells is tested and the average lifetime of this sample is found to be 315 hours.
The 315 hours is the value of a: statistic
A statistic is defined as a characteristic of a sample. It is used to estimate the value of a population parameter.
Just like here where a random sample of 650 power cells were taken for a test. And 315 hours is an example of a statistic.