Question

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Answer 1

Answer:

x + 2tan X . sec X / X

Step-by-step explanation:

The derivatives of trigonometric functions is as follows

* d/dx (sin x) = cos x

* d/dx (cos x) = - sin X

* d/dx (tan x) = sec ^2 X

* d/dx (Cot x) = -cosec^2 X

* d/dx (sec x) = tan x . sec x

* d/dx (cosec x) = -cot x . cosec x

and so the derivative of sec is tanx . sec x

d/dx x - sec x

the derivative of variables is considered 1.

since we remove 1 from their exponent they'll have 0 as their exponent which can only mean the end value is 1.

so d/dx of X is = 1

d/dx od -sec X is = -tan X . Sec X based on the general derivative properties above.

in conclusion the final answer is = x + 2tan X . sec X / X