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3 years ago

Please solve AND CHECK at least one of these problems, giving brainliest

Mathematics

2 answers:

Leya [2.2K]3 years ago

3 0

Answer:

x ≥ - 14

Step-by-step explanation:

$5x + 15 >= 3x - 13\\2x >= -28\\x >= -14$

gavmur [86]3 years ago

3 0

Answer:

x >= -14

Step-by-step explanation:

5(x+3)>=3x-13

distribute left side

5x+15 >= 3x-13

move variables to one side, and numbers to other

5x-3x >= -13-15

2x >= -28

divide both sides by 2 to isolate x

x >= -14

this is the answer

check:

5(-14+3) >= 3(-14)-13

-55 >= -55 -> correct

check 2:

5(-13+3) >= 3(-13)-13

-50 >= -52 -> correct

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What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?

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3 years ago

Of 560 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared

frutty [35]

Answer:

a) (0.5256,0.5944)

c) Criticism is invalid

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 560

Proportion of mislabeled = 56%

$\hat{p} = 0.56$

a) 90% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64$

Putting the values, we get:

$0.56\pm 1.64(\sqrt{\dfrac{0.56(1-0.56)}{560}}) = 0.56\pm 0.0344\\\\=(0.5256,0.5944)$

b) Interpretation of confidence interval:

We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.

c) Validity of criticism

Conditions for validity:

$np > 10\\n(1-p)>10$

Verification:

$560\times 0.56 = 313.6>10\\560(1-0.56) = 246.4>10$

Both the conditions are satisfied. This, the criticism is invalid.

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3 years ago