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melamori03 [73]
2 years ago
6

Molly has biweekly gross earnings of $839. 52. By claiming 1 more withholding allowance, Molly would have $16 more in her take h

ome pay. How many withholding allowances does Molly currently claim? a. 1 b. 2 c. 3 d. 4.
Mathematics
1 answer:
fredd [130]2 years ago
6 0

Molly currently claims 2 withholding allowances which can be determined by using rules of allowance.

<h2>Given that,</h2>

Molly has biweekly gross earnings of $839. 52.

By claiming 1 more withholding allowance,

Molly would have $16 more in her take-home pay.

<h3>We have to determine,</h3>

How many withholding allowances does Molly currently claim?

<h3>According to the question,</h3>

Molly has biweekly gross earnings of $839. 52.

By claiming 1 more withholding allowance,

Molly would have $16 more in her take-home pay.

The withholding allowance is used by a person to pay less amount of tax on his or her income to the government.

Molly has biweekly gross earnings of $839. 52.

By claiming 1 more withholding allowance,

Molly would have $16 more in her take-home pay.

Therefore,

It is given that Molly has taken 1 more withholding allowance to pay tax less by the amount of $16.

So he must have possessed at least 1 allowance previously and added 1 more.

So, the minimum number of allowance possessed by Molly = 2

Hence, Molly currently claims 2 withholding allowances.

For more details about Income Tax refer to the link given below.

brainly.com/question/1708567

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His new time compared with the old time was increased by factor of 2

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration (m / s²)v = final velocity (m / s)</em>

<em>u = initial velocity (m / s)</em>

<em>t = time taken (s)</em>

<em>d = distance (m)</em>

Let us now tackle the problem!

This problem is about Kinematics.

In this problem we assume that the unicorn is moving at a constant speed so that the acceleration is zero.

<u>Given:</u>

first distance = d₁ = 50 miles

second distance = d₂ = 300 miles

v₂ = 3 v₁

<u>Unknown:</u>

t₂ : t₁ = ?

<u>Solution:</u>

To find his new time , we will use the following formula.

v_2 = 3 v_1

\frac{d_2}{t_2} = 3 \times \frac{d_1}{t_1}

\frac{300}{t_2} = 3 \times \frac{50}{t_1}

\frac{300}{t_2} = \frac{150}{t_1}

t_2 = \frac{300}{150} \times t_1

\large {\boxed {t_2 = 2 \times t_1} }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Sperm , Whale , Travel

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Step-by-step explanation:

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