Hey there :)
Let
p represent the number of bags to be bought
We need to collect
30 stickers and each
bag has
3 stickers
3p = 30
↑ ↑
Number of stickers in a bad Number of stickers to be collected
=
p = 10We need to buy 10 bags of crisps to have 30 stickers
The two dot plots are missing, so i have attached it.
Answer:
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
Step-by-step explanation:
From the attached image, we are told to compare the means for each plot to the nearest tenth.
Mean = Σx/n
Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;
(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133
Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles
Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143
Mean of miles run at the end of the school year = 143/14 = 10.2 miles
Thus;
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
Step-by-step explanation:
Answer:
y = (1/4)x+3
Step-by-step explanation:
Answer:
<h3>Mass of B in Kg = -558.44kg</h3>
Step-by-step explanation:
LET'S DO THIS!
Total mass of A, B and C = 1.95kg
Mass of A = 700 kg
Mass of B = 4x the mass of c (4 x C) which is 4c
Mass of C = ? ( let's call it C )
<h3>Adding all together </h3>
700 + 4c + C = 1.95
<h3>Add like terms</h3>
700 + 5C = 1.95
5C = 1.95 - 700
5C = -698.05
C = -698.05 ÷ 5
<h3>C = -139.61</h3>
<h3>To find B now </h3><h3>Remember they said B is 4 times the mass of C and C = -139.61</h3>
therefore B = 4 × -139.61
<h3>B = -558.44 kg </h3>
<h3>To check if we are correct, we add the masses of A, B and C to see if it equals their total mass which is 1.95kg</h3>
<h3>Using your calculator: </h3>
= 700 + ( -558.44 ) + ( -139.61 )
= 700 - 558.44 -139.61
= 1.95 kg
Which makes us CORRECT ✅.
<h3>Hope this helps.</h3><h3>Good luck ✅.</h3>
