Answer:
With 250 minutes of calls the cost of the two plans is the same
Step-by-step explanation:
We must write an equation to represent the cost of each call plan.
<u>For the first plan</u>
Monthly fee
$ 13
Cost per minute
$ 0.17
If we call x the number of call minutes then the equation representing the cost c for this plan is:
<u>For the second plan</u>
monthly fee
$ 23
Cost per minute
$ 0.13
If we call x the number of call minutes then the equation representing the cost c for this plan is:
To know when the cost of both plans are equal, we equate the two equations and solve for x.
With 250 minutes of calls the cost of the two plans is the same: $55.5
1. s<span>olve the proportion k/5=5/125.
First reduce 5/125.
5/125 = 1/25
Now you can cross multiply.
25k = 5
k = 5/25
k = 1/5
</span><span>d) 1/5
2. </span><span>round the answer of 0.4x-0.2=2.5 to two decimal places.
</span>0.4x=2.7
x = 6.75
<span>b) -6.75
3. </span><span>what is the y-intercept of 4x-3y=-12?
The y-intercept is when x = 0.
4(0) - 3y = -12
-3y = -12
y = 4
</span>d) 4
Answer: $5661 will be in the account 10 years later
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 5000
r = 1.25% = 1.25/100 = 0.0125
n = 1 because it was compounded once in a year.
t = 10 years
Therefore,
A = 5000(1 + 0.0125/1)^1 × 10
A = 5000(1.0125)^10
A = 5000(1.0125)^10
A = $5661