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2 years ago

In the diagram below, C is the midpoint of AB. If AC is 4 centimeters, what is

Mathematics

1 answer:

Strike441 [17]2 years ago

6 0

Answer:

The answer is B. 4cm

Step-by-step explanation:

Since it is the midpoint AC is always going to be the same as CB if C is the midpoint.

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which of the following best describes 4^2/3? a. sq root of 16, b. cube root of 4, c. sq root of four, d. cube root of 16

son4ous [18]

Answer: D) cube root of 16

================================================

Explanation:

The rule we use is

$x^{m/n} = \sqrt[n]{x^m}$

In this case, x = 4, m = 2 and n = 3.

So,

$x^{m/n} = \sqrt[n]{x^m}\\\\\\4^{2/3} = \sqrt[3]{4^2}\\\\\\4^{2/3} = \sqrt[3]{16}\\\\\\$

Showing that the original expression turns into the cube root of 16.

4 0

2 years ago

drug sniffing dogs must be 95% accurate in their responses because their handlers don't want them to miss durgs and also don't w

GenaCL600 [577]

Answer:

95% Confidence interval: (0.8449,0.9951)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 50

Number of times the dog is right, x = 46

$\hat{p} = \dfrac{x}{n} = \dfrac{46}{50} = 0.92$

95% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting the values, we get:

$0.92 \pm 1.96(\sqrt{\dfrac{0.92(1-0.92)}{50}})\\\\ = 0.92\pm 0.0751\\\\=(0.8449,0.9951)$

(0.8449,0.9951) is the required 95% confidence interval for the proportion of times the dog will be correct.

7 0

2 years ago

Margo borrows $2000, agreeing to pay it back with 7% annual interest after 17 months. How much interest

julia-pushkina [17]

Answer:

1000

Step-by-step explanation:

bc i dont know thats why hope it helped

7 0

2 years ago

Please help I will give brainlyiest fast please help fast

lana [24]

Answer:

A. 49.

Step-by-step explanation:

<u>Given equation:</u>

-11 2/3 * (-4 1/5)

<u>Simplify, then solve:</u>

-11 2/3 * (-4 1/5)
= -35/3 * (-21/5)
= $\frac{-35 * (-21)}{3 * 5}$
= 735/15
= 49.

Your answer is A. 49.

5 0

2 years ago

Information on a packet of seeds claims that 93% of them will germinate. Of the 200 seeds that I planted, only 175 germinated. (

Anvisha [2.4K]

Answer:

We reject H₀

we accept Hₐ seeds in the packet would germinate smaller than 93%

Step-by-step explanation:

Test of proportions

One tail-test (left side)

93 % = 0.93

p₀ = 0,93

1.- Hypothesis

<h3>H₀ ⇒ null hypothesis p₀ = 0.93</h3><h3>Hₐ ⇒ Alternative hypothesis p = 0.875</h3><h3>2.-Confidence interval 95 %</h3><h3>α = 0,05 </h3><h3>and </h3><h3>z(c) = - 1.64</h3><h3>3.- Compute z(s)</h3><h3>z(s) = (p - p₀)/√(p₀*q₀)/n z(s) = (0.875-0.93)/√0.93*0.07)200</h3><h3>z(s) = - 0,055/ √0.0003255</h3><h3>z(s) = - 0.055/ 0.018</h3><h3>z(s) = - 3,06</h3><h3>4.-Compere z(c) and z(s)</h3><h3>z(s) < z(c) -3.06 < -1.64</h3><h3>z(s) is in rejection region, we reject H₀</h3>

5 0

3 years ago