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aleksandrvk [35]
3 years ago
8

(1) -3x-4y+11z from-9y+6z-3x (2) 3x⁴-4x³+7x-2 from 9-7x⁴+6x³-2x²-11x​

Mathematics
1 answer:
romanna [79]3 years ago
6 0

Answer:

1) 5y + 5z

2) 10x⁴ - 10x³ + 2x² + 18x - 11

Step-by-step explanation:

Given the subtraction of the following polynomial expressions:

<h2>(1) -3x - 4y + 11z from -9y + 6z - 3x</h2>

In order to make it easier for us to perform the required mathematical operations, we must first rearrange the terms in the <em>subtrahend</em> by alphabetical order.

-3x - 4y + 11z  

-3x - 9y + 6z  ⇒ This is the <u><em>subtrahend</em></u>.

Now, we can finally perform the subtraction on both trinomials:

\displaystyle\mathsf{\left \ \quad\:\:\:\:{-3x - 4y + 11z} \atop -\quad{\underline{-3x - 9y + 6z\:\:\underline}} \right.}

In the <em>subtrahend</em>, the coefficients of x and y are both negative. Thus, performing the subtraction operations on these coefficients transforms their sign into positive.  

\displaystyle\mathsf{\left \ \quad\:\:\:\:{-3x - 4y + 11z} \atop -\quad{\underline{-3x - 9y + 6z\:\:\underline}}\right.} \\\qquad\sf {\qquad\:\:\:0x\:+\:5y\:+5z

The difference is: 5y + 5z.

<h2>(2) 3x⁴- 4x³ + 7x - 2 from 9 - 7x⁴ + 6x³- 2x² - 11x​</h2>

Similar to the how we arranged the given trinomials in Question 1, we must rearrange the given polynomials in descending degree of terms before subtracting like terms.

3x⁴- 4x³ + 7x - 2           ⇒  Already in descending order (degree).

9 - 7x⁴ + 6x³- 2x² - 11x​   ⇒  -7x⁴ + 6x³- 2x² - 11x​ + 9

In subtracting polynomials, we can only subtract <u>like terms</u>, which are terms that have the same variables and exponents.  

\displaystyle\mathsf{\left \ \quad\:\:{3x^4\:-4x^3\:+\:0x^2\:+\:7x\:-\:2} \atop -\quad{\underline{-7x^4\:+6x^3\:-2x^2\:-11x\:+\:9 \:\:\underline}}\right.}  

In the <u><em>minuend</em></u><em>, </em>I added the "0x²" to make it less-confusing for us to perform the subtraction operations.  

The same rules apply in terms of coefficients with negative signs in the subtrahend, such as: -7x⁴, - 2x², and - 11x​ ⇒  their coefficients turn into positive when performing subtraction.  

\displaystyle\mathsf{\left \ \quad\:\:{3x^4\:-4x^3\:+\:0x^2\:+\:7x\:-\:2} \atop -\quad{\underline{-7x^4\:+6x^3\:-2x^2\:-11x\:+\:9 \:\:\underline}}\right.} \\\qquad\sf {\qquad\:\:10x^4-10x^3+2x^2+18x\:-11  

Therefore, the difference is: 10x⁴ - 10x³ + 2x² + 18x - 11.

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diameter \frac{12}{5} ​times  19\frac{3}{4}  that is

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Check the forward differences, and denote the <em>n</em>-th difference by <em>b </em>(<em>n</em>). That is,

<em>b </em>(<em>n</em>) = <em>a </em>(<em>n</em> + 1) - <em>a </em>(<em>n</em>)

These so-called first differences are

<em>b</em> (1) = <em>a</em> (2) - <em>a</em> (1) = 25 - 7 = 18

<em>b</em> (2) = <em>a</em> (3) - <em>a</em> (2) = 51 - 25 = 26

<em>b </em>(3) = <em>a</em> (4) - <em>a</em> (3) = 85 - 51 = 34

<em>b</em> (4) = <em>a </em>(5) - <em>a</em> (4) = 127 - 85 = 42

Now consider this sequence of differences,

18, 26, 34, 42, …

and notice that the difference between consecutive terms in this sequence <em>b</em> is 8:

26 - 18 = 8

34 - 26 = 8

42 - 34 = 8

and so on. This means <em>b</em> is an arithmetic sequence, and in particular follows the rule

<em>b</em> (<em>n</em>) = 18 + 8 (<em>n</em> - 1) = 8<em>n</em> + 10

for <em>n</em> ≥ 1.

So we have

<em>a </em>(<em>n</em> + 1) - <em>a </em>(<em>n</em>) = 8<em>n</em> + 10

or, replacing <em>n</em> + 1 with <em>n</em>,

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 8 (<em>n</em> - 1) + 10

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 8<em>n</em> + 2

We can solve for <em>a</em> (<em>n</em>) by iteratively substituting:

<em>a</em> (<em>n</em>) = [<em>a</em> (<em>n</em> - 2) + 8 (<em>n</em> - 1) + 2] + 8<em>n</em> + 2

<em>a</em> (<em>n</em>) = <em>a </em>(<em>n</em> - 2) + 8 (<em>n</em> + (<em>n</em> - 1)) + 2×2

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and so on. The pattern should be clear; we end up with

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