P²÷4-m; use m=3, and p=4

98 people who were vaccinated were seniors. • 80 people reported a chronic disease or long-term health problem, such as heart or

Fittoniya [83]

Answer:

16.3 is the percent of seniors reported a chronic medical condition chronic is long term recovery acute is short term recovery

Step-by-step explanation:

7 0

3 years ago

Can anyone solve this?

lesantik [10]

Answer:

Step-by-step explanation:

1. h>13

2. n_> 12

4 0

3 years ago

Which inequality will have a solid boundary line and a shaded region above its graph? x − y ≥ 3 2x − 3y ≤ 3 3y − x < 2 2x + y

LenKa [72]

<span>x − y ≥ 3 ... > stands for above on a graph, and the line under it _ stands for shaded.</span>

7 0

3 years ago

A nurse collected data about the average birth weight of babies in the hospital that month. Her data is shown using the dot plot

mixer [17]

Answer:

The values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

Step-by-step explanation:

The data provided is as follows:

X Frequency

8 0

8.1 0

8.2 2

8.3 2

8.4 2

8.5 3

8.6 0

8.7 1

8.8 0

8.9 1

9 0

So, the actual data is:

S = {8.2 , 8.2 , 8.3 , 8.3 , 8.4 , 8.4 , 8.5 , 8.5 , 8.5 , 8.7 , 8.9 }

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

Minimum (shown at the bottom of the chart)
First Quartile (shown by the bottom line of the box)
Median (or the second quartile) (shown as a line in the center of the box)
Third Quartile (shown by the top line of the box)
Maximum (shown at the top of the chart).

The data set is arranged in ascending order.

The minimum value is, Min. = 8.2

The lower quartile is,

$[\frac{n+1}{4}]^{th}\ obs.=[\frac{11+1}{4}]^{th}\ obs.=3^{rd }\ obs. =8.3$ ,

Q₁ = 8.3.

The median value is,

$[\frac{n+1}{2}]^{th}\ obs.=[\frac{11+1}{2}]^{th}\ obs.=6^{th}\ obs.=8.4$

Median = 8.4

The upper quartile is,

$[\frac{3(n+1)}{4}]^{th}\ obs.=[\frac{3(11+1)}{4}]^{th}\ obs.=9^{th }\ obs. =8.5$ ,

Q₃ = 8.5.

The maximum value is, Max. = 8.9.

So, the values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

5 0

3 years ago

How do you add vectors? Add the vector <3,4> to the vector that goes 7 units at an angle of 2π/3.

lawyer [7]

Answer:

The sum of the two vectors is the vector <-0.5 , 4+3.5 $\sqrt{3}$ >

Step-by-step explanation:

The horizontal component (x) of a vector whose magnitude is b units and its direction is Ф° is b cos Ф

The vertical component (y) of a vector whose magnitude is b and its direction is Ф is b sin Ф

The vector is <b cos Ф , b sin Ф>

∵ The vector goes 7 units at an angle $\frac{2\pi }{3}$

- That means its magnitude is 7 and its direction is $\frac{2\pi }{3}$

∴ x = 7 cos( $\frac{2\pi }{3}$ )

∴ y = 7 sin( $\frac{2\pi }{3}$ )

∵ cos( $\frac{2\pi }{3}$ ) = $-\frac{1}{2}$

∵ sin( $\frac{2\pi }{3}$ ) = $\frac{\sqrt{3}}{2}$

- Substitute them in x and y

∴ x = (7)( $-\frac{1}{2}$ )

∴ x = -3.5

∴ y = (7)( $\frac{\sqrt{3}}{2}$ )

∴ y = 3.5 $\sqrt{3}$

∴ The vector is <-3.5 , 3.5 $\sqrt{3}$ >

Now lets add the vectors by adding xs and ys components

∵ <3 , 4> + <-3.5 , 3.5 $\sqrt{3}$ > = <3 + -3.5 , 4 + 3.5 $\sqrt{3}$ >

∴ <3 , 4> + <-3.5 , 3.5 $\sqrt{3}$ > = <-0.5 , 4+3.5 $\sqrt{3}$ >

∴ The sum of the two vectors is the vector <-0.5 , 4+3.5 $\sqrt{3}$ >

5 0

3 years ago

P²÷4-m; use m=3, and p=4​

P²÷4-m; use m=3, and p=4