Answer:
There is 55% probability that I order both the sandwich and soup
Step-by-step explanation:
P(sandwich) = 0.8
P(Soup) = 0.7
P(neither sandwich nor soup) = 0.05
P(sandwich or soup) = 1 - P(neither sandwich nor soup)
P(sandwich or soup) = 1 - 0.05 = 0.95
P(Sandwich & Soup) = x
P(Sandwich only) = 0.8 - x
P(Soup only) = 0.7 - x
P(sandwich or soup) = P(Sandwich only) + P(Soup only) + P(Sandwich & Soup)
Note that P(neither sandwich nor soup) has already been used to get the P(sandwich or soup) and should not be included in the above formula. Don't make that mistake!
0.95 = 0.8 - x + 0.7 - x + x
0.95 = 1.50 - x
x = 1.50 - 0.95
x = 0.55
There is 55% probability that I order both the sandwich and soup
Answer:
24 ounces for 6.00
Step-by-step explanation:
it has more in it.
Answer:
The probability is ![P(X > x) = 0.0013499](https://tex.z-dn.net/?f=P%28X%20%3E%20x%29%20%3D%200.0013499)
Step-by-step explanation:
From the question we are told that
The mean is ![\mu = 25](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%2025)
The standard deviation is ![\sigma = 5 \ minutes](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%205%20%5C%20minutes)
The random number ![x = 40](https://tex.z-dn.net/?f=x%20%3D%2040)
Given that the time taken is normally distributed the probability is mathematically represented as
![P(X > x) = P[\frac{X -\mu}{\sigma } > \frac{x -\mu}{\sigma } ]](https://tex.z-dn.net/?f=P%28X%20%3E%20x%29%20%3D%20%20P%5B%5Cfrac%7BX%20-%5Cmu%7D%7B%5Csigma%20%7D%20%3E%20%5Cfrac%7Bx%20-%5Cmu%7D%7B%5Csigma%20%7D%20%5D)
Generally the z-score for the normally distributed data set is mathematically represented as
![z = \frac{X - \mu}{\sigma }](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7BX%20%20-%20%5Cmu%7D%7B%5Csigma%20%7D)
So
![P(X > x) = P[Z > \frac{40 -25}{5 } ]](https://tex.z-dn.net/?f=P%28X%20%3E%20x%29%20%3D%20%20P%5BZ%20%3E%20%5Cfrac%7B40%20-25%7D%7B5%20%7D%20%5D)
![P(X > x) = 0.0013499](https://tex.z-dn.net/?f=P%28X%20%3E%20x%29%20%3D%200.0013499)
This value is obtained from the z-table