Contraction of the cremaster muscles in the human reproductive system helps to move the testes closer to the body, so they can easily absorb body heat.

<h3>What is reproduction?</h3>

Reproduction can be defined as a biological process through which all living parent organisms produce their offspring, especially through mating.

During the reproduction process, contraction of the cremaster muscles in the human reproductive system helps to move the testes closer to the body, so they can easily absorb body heat.

Read more on reproduction here: brainly.com/question/2538465

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3 0

2 years ago

Why is it important to distress?

Anna35 [415]

I agree with the person above.
Prolonged stressing causes mental illnesses such as depression, anxiety, and personality disorders.
It causes physical illnesses such as cardiovascular disease, high blood pressure, abnormal heart rhythms, heart attacks, heart disease, and strokes.

Ways to distress are things like exercising, eating healthy, meditate, take a deep breath in and out, and find a hobby that helps you distress. Also I would full heartedly recommend watching Bob Ross.
How this helps

6 0

3 years ago

If x^2 = 7 , x^4 + y^2 = 50, and y + w = 3, which of the following is possible<br> Value of W

Colt1911 [192]

Answer:

2 OR4 ; both correct

Explanation:

x^2=7

x^4+y^2=50

x^4=(x^2)^2=(7)^2=49 --> 49+y^2=50

y^2=50-49=1 --> y=± $\sqrt{1}$ --> y=±1

+1 or -1 both possible --> solve both

+1+w=3 --> w = 3 - 1 = 2

-1+w=3 --> w = 3 + 1 = 4

7 0

3 years ago

At a large corporation, the distribution of years of employment for the employees has mean 20.6 years and standard deviation 5.3

Cerrena [4.2K]

Answer:

Yes

Explanation:

The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma}\\\\where\ \mu=mean.\sigma=standard\ deviation, x=raw\ score.\\\\For\ a \ sample\ size\ n:\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }$

For a normal distribution with a mean of μ and standard deviation σ, For any sample size (n) drawn from this population, the sample mean is normally distributed, with mean $\mu_x=\mu$ and standard deviation $\sigma_x=\frac{\sigma}{\sqrt{n } } \\\\$ .

Hence given that a mean of μ = 20.6 years and standard deviation σ = 5.3 years, for a sample size of 100:

mean $\mu_x=\mu=20.6\ years$ and standard deviation $\sigma_x=\frac{\sigma}{\sqrt{n } } =\frac{5.3}{\sqrt{100} }=0.53\ years \\\\$ .

7 0

3 years ago