Ask question

Ask question

All categories

3 years ago

14

Drag the tiles to the correct boxes to complete the pairs.

1 answer:

lianna [129]3 years ago

6 0

Answer:

i dont get how this is a math question

and can you post a screenshot so i can understand it better

Step-by-step explanation:

You might be interested in

Hello any help would be appreciated ❤ Thank you ❤

Alex787 [66]

I know that B) is 3,500. the exact form for A) is 4.5x 10 to the power of 11 or 450000000000

7 0

3 years ago

Read 2 more answers

What is the slope of a line passing through the following points (3,2) (-6,2)

yan [13]

Vas happenin!!!
Hope your day is good

So to find slope you use this equation: y2-y1/x2-x1

2-2/-6 -3

0/-9

Your slope is 0

Hope this helps you out

*smiles*

6 0

3 years ago

Hey there! BRAINLIEST! Lol, because I have no life whatsoever, but um if your on this question. Thank you. Please help me out! I

Anni [7]

Answer:

LCD=5 Final answer= 5/5 -> 5/1 -> to 5

Step-by-step explanation:

First, find the LCD(least common denominator) which is 5. This is done listing the multiples of each number in this case the lowest number is 5.

3/5 will stay the same but for 1/10 you need to convert it to the fraction 2/5 Next add the fractions together to get 3/5 + 2/5 = 5/5 of 5/1 or just 5

4 0

2 years ago

Read 2 more answers

What are 3 numbers between 0.33 and 0.34

ddd [48]

0.330000000001, 0.330000000002, 0.339999999999

4 0

3 years ago

Read 2 more answers

Pls can someone help me and have it right

dangina [55]

Answer:

Problem 1:

a. x=2

b. x=3

c. x=1

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Step-by-step explanation:

Given in problem 1:

(a). The equation is $\frac{x}{6} > 1$

It holds true for all values of $x> 6$ .

Let us say $x=12$ ,

$\frac{x}{6}=\frac{12}{6} =2$ which is greater than 1.

(b). The equation is $\frac{x}{6} < 1$

It holds true for all values of $x< 6$ .

Let us say $x=3$

$\frac{x}{6} =\frac{3}{6} =\frac{1}{2}$ which is less than 1.

(c). The equation is $\frac{x}{6} = 1$

It holds true for only $x= 6$ .

Let us say $x=6$ ,

$\frac{x}{6} =\frac{6}{6}=1$ which is equal to 1.

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Therefore these are the values which hold true to the equation in problem 1 and 2.

8 0

3 years ago