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Dovator [93]
2 years ago
8

Solve the following system of equations for all three variables.

Mathematics
1 answer:
Assoli18 [71]2 years ago
6 0

Eliminate z by combining the first two equations:

(7x + 9y - 2z) - 2 (x - 9y - z) = 9 - 2 (-3)

7x + 9y - 2z - 2x + 18y + 2z = 9 + 6

5x + 27y = 15

Eliminate z by combining the last two equations:

5 (x - 9y - z) + (-8x - 9y + 5z) = 5 (-3) + 6

5x - 45y - 5z - 8x - 9y + 5z = -15 + 6

-3x - 54y = -9

x + 18y = 3

Now eliminate x from these two new equations and solve for y :

(5x + 27y) - 5 (x + 18y) = 15 - 5 (3)

5x + 27y - 5x - 90y = 15 - 15

-63y = 0

y = 0

It follows that

x + 18y = x = 3

and

x - 9y - z = 3 - z = -3   ⇒   -z = -6   ⇒   z = 6

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Simplify: -|-15|<br><br> please answer correctly i'll give brainliest and 5-star rating.
12345 [234]

Answer:

-15

Step-by-step explanation:

<u>Definition of absolute value: </u>

<em>Distance from zero on a number line. </em>

<em />

Imagine a number line with 0 in the middle of it. Now mark the number 3 on it. Also mark the <em>opposite </em>of 3, which is -3. What is the <u>distance</u> from zero to those 2 points? it's 3.

This is exactly like saying |3| = 3 and |-3| = 3

Even if the number inside absolute value is negative, it <em><u>simplifies</u></em> to the positive of the same number.

_______________________________

So let's talk about your problem.

-|-15|

> the absolute value simplifies to 15

-|-15| = - 15

So that ends up being your answer.

-15

Hope this helps!!!!!!!

7 0
3 years ago
What are the degrees of freedom for Student's t distribution when the sample size is 19? d.F. = Use the Student's t distribution
liq [111]

Answer:

a) 18

b) 2.101

Step-by-step explanation:

a) What are the degrees of freedom for Student's t distribution when the sample size is 19?

Degrees of freedom = n - 1

Where n = sample size

= 19 - 1

= 18

b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.

(Round your answer to three decimal places.)

We would be determining these using the t distribution table

1 - 0.95 = 0.05 ( for two tailed)

Or

0.05/2 = 0.025(one - tailed)

Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101

7 0
3 years ago
5.
masha68 [24]

Answer:

2453t3

step-by-step explanation:

1324=56476=35=2424536=45346=5768=77=5=575=775

7 0
3 years ago
HELP ME PLEASEEEEEEEEE
OLEGan [10]

Answer:

116 c

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Write an equation and solve for the value of x stare the reason for your equation
Troyanec [42]

Remember that the total of the angles always equals 180 degrees

4x + 2 + 8 + 6x + 30 = 180

Now solve

4x + 2 - 2 + 8 + 6x + 30 = 180 - 2

4x + 8 - 8 + 6x + 30 = 178 - 8

4x + 6x + 30 - 30 = 170 - 30

4x + 6x = 140

10x = 140

10x ÷ 10 = 140 ÷ 10

x = 14


Now that we know what x is we can fill in the blanks

4(14) + 2

58 + 2

58

Angle O is 58 degrees


8 + 6(14)

8 + 84

92

Angle R is 92 degrees


To check we can add them all up

30 + 58 + 92 = 180


x = 14

4 0
3 years ago
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