Answer:
sheeeexxkxkx
Step-by-step explanation:
dyddhjdjdjdj
Answer:
![(-7,4]\text{ or }\{x|-7](https://tex.z-dn.net/?f=%28-7%2C4%5D%5Ctext%7B%20or%20%7D%5C%7Bx%7C-7%3Cx%5Cleq%204%5C%7D)
Step-by-step explanation:
The domain is the span of x-values covered by the function.
From the graph, we can see that the graph covers all the x-values from x=-7 to x=4.
However, note that closed and open circles. There is an open circle at x=-7, which means that the domain excludes x=-7. However, the circle at x=4 is closed, meaning it is included in the domain.
Therefore, the domain is, in interval notation:
![(-7,4]](https://tex.z-dn.net/?f=%28-7%2C4%5D)
We use parentheses on the left because we do not include -7. And we use brackets on the right because we <em>do </em>include the 4.
And in set notation, this is:
Answer: yes they probably are because they can be any size
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
