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Umnica [9.8K]
3 years ago
13

Find all complex solutions of 13x^2-5x+1=0 btw it doesn’t let me do the +- sign

Mathematics
2 answers:
miskamm [114]3 years ago
5 0

Answer:

Step-by-step explanation:

You can make it by using division +/-. The keystrokes are

+

/

-

a = 13

b = -5

c = 1

x = [-(-5) +/- sqrt( (-5)^2 - 4*13*1) )] / 2

x = [ 5 +/- sqrt( 25 - 52) ] / 2

x = [ 5 +/- sqrt(-27)]/2

x = [5 +/- 3 sqrt(3)i ] / 2

x = 5/2 +/- 3/2 * sqrt(3) i

So x1 = 2.5 + 1.5 sqrt(3)i    or

x2 = 2.5 - 1.5 sqrt(3)i

skad [1K]3 years ago
5 0

Answer: it was 97 I did the test and got it right

Step-by-step explanation:

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If EF bisects CD.CG = 5x - 1, GD = 7x-13, EF = 6x - 4, and GF = 13. find EG.
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Answer:

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Step-by-step explanation:

* Lets explain how to solve the problem

- If a line bisects another line that means the point of intersection

 divides the second line into two equal parts

∵ EF bisects CD at G

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∴ 7x - 13 = 5x - 1

* Lets solve the equation

∵ 7x - 13 = 5x - 1

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