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Deffense [45]
2 years ago
7

What is the midpoint of the line segment with endpoints (-2,-4) and (4.6)?​

Mathematics
1 answer:
FrozenT [24]2 years ago
8 0

-0.7 im guessing

it might not be right but i tried because

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A bike wheel. A bike wheel is 26 inches in diameter. What is the bike wheel's diameter in millimeters (1 inch = 25.4 millimeters
Salsk061 [2.6K]

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(4.1.4) Let X and Y be Bernoulli random variables. Let Z = X + Y. a. Show that if X and Y cannot both be equal to 1, then Z is a
Fynjy0 [20]

Step-by-step explanation:

Given that,

a)

X ~ Bernoulli (p_x) and Y ~ Bernoulli (y_x)

X + Y = Z

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and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0

If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,

Therefore Z is a Bernoulli random variable

b)

If X and Y can not be both equal to  1

then,

p_z = P(X=1 or Y=1)\\

p_z = P(X=1)+P(Y=1)-P(=1 and Y =1)

p_z = P(x=1)+P(Y=1)\\\\p_z=p_x+p_y

c)

If both X = 1 and Y = 1 then Z = 2

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since a  Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution

7 0
3 years ago
A student concludes that for all values of x,x^2+x+1 produces a prime number. Which value of x serves as counterexample to prove
Dafna11 [192]

Answer:

j

Step-by-step explanation:

Substitute the given values into x² + x + 1 and check if result is prime

x = - 4

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(- 2)² - 2 + 1 = 4 - 2 + 1 = 3 ← prime

(- 3)² - 3 + 1 = 9 - 3 + 1 = 7 ← prime

4² + 4 + 1 = 16 + 4 + 1 = 21 ← not prime

x = 4 serves as a counterexample to disprove this conclusion

5 0
3 years ago
13(6x – 5) – x = 13 – 2(x + 1
elena-s [515]

Answer:

Step-by-step explanation:

13(6x-5)-x=13-2(x+1)\\78x-65-x=13-2x-2\\77x-65=11-2x\\77x+2x=11+65\\x=76/79\\x=0.9620

6 0
3 years ago
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