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Airida [17]
2 years ago
10

The major difference between a calculator and a computer, when performing calculations, is that a

Computers and Technology
1 answer:
leva [86]2 years ago
7 0
Well a computer by far has more processing power than a calculator... then again it all depends on how crazy your hardware is I suppose. In the way of human intervention, a calculator requires you input information via buttons, whereas a computer's CPU performs operations on a dime, and all the time at that. So given this information, I would choose A. Although I wouldn't bet my life on it, things like this have lots of variables to consider.
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How to take a pic with a cumputer
sattari [20]

Answer:

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4 0
2 years ago
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A soft drink company recently surveyed 12,467 of its customers and found that approximately 14 percent of those surveyed purchas
Mnenie [13.5K]

Given Information:

Total number of customers = 12,467

Customers who purchase one or more energy drinks per week = 14%

Customers who prefer citrus flavored energy drinks = 64% of customers who purchase one or more energy drinks per week

Required Information:

1. the approximate number of customers in the survey who purchase one or more energy drinks per week

2. the approximate number of customers in the survey who prefer citrus flavored energy drinks

Code with Explanation:

#include <iostream>

using namespace std;

int main()

{

   int customers = 12467;  // total no. of customers given

   int buy_drink;  // to store the number of customers who buy one or more energy drinks per week

   int citrus_drink;  // to store the number of customers who prefer citrus flavored energy drinks

 

   buy_drink = customers*0.14;  // multiply total number of customers with the % of customers who buy energy drinks

   citrus_drink = buy_drink*0.64;  // multiply no. of customers who buy one or more energy drinks per week with % of customers who prefer citrus flavor

// display the results calculated above

   cout<<"Total number of customers: "<<customers<<endl;

   cout<<"Number of customers who buy one or more drinks per week: "<<buy_drink<<endl;

   cout<<"Number of customers who prefer citrus flavored drinks per week: "<<citrus_drink<<endl;

   return 0;

}

Output:

Total number of customers: 12467

Number of customers who buy one or more drinks per week: 1745

Number of customers who prefer citrus flavored drinks per week: 1116

7 0
3 years ago
I'm stuck on this Java exercise problem and don't know how to organize my code with proper formatting and it's not helping that
Volgvan

In your "count spaces method" before the for loop, you want to declare an int variable (let's call it spc)

then, each time you find that charat, spc++.


also, the string must be declared in the main method, not the spaces count method.


The actual code:


public class CountSpaces{

public static void main(String[] args){

String instring = "(your quote here)";

int spaces = calculateSpaces(instring);

System.out.println("The number of spaces is " + spaces);

}

public static int calculateSpaces(String in){

int spc = 0;

for(int i= 0; i<in.length; i++){

if(in.charAt(i)== ' '){

spc++;

}

}

return spc;

}

}


that should be it.  If you have any questions, feel free to reach out.

4 0
3 years ago
In the reaction __H2 + O2 → 2H2O, what coefficient should be placed in front of H2 to balance the reaction?
malfutka [58]
The answer is:  [B]:  " 2 " .
_____________________________________________
Explanation:
____________________________________
Given the chemical equation:
____________________________________

     <u> ? </u> H₂ + O₂ → 2 H₂<span>O   ;
____________________________________________
</span>      → <span> We are asked, "What coefficient, if any — should be put in front of the:  " H</span>₂ " ;
__________________________________________________
          (which is on the "left-hand side" side of the chemical equation given—      the "reactants") ;

     →  to get a balanced chemical equation?
__________________________________________________
 →  Let us examine the "right-hand side" of this chemical equation—the product(s).  In this case, the "product" given is:  " 2 H₂O " .  

So, on the "right hand side", we have:
__________________________________________________
     1)  4 "H's" → {Two "H₂" 's = 2 * 2 = "4 H's"} ;  <u><em>and</em></u>:
     2)  2 "O's" → { Two "O's").
__________________________________________________
   So, the left-hand side should have:
__________________________________________________
     1)  4 "H's" ;  <u><em>and</em></u>:
     2)  2 "O's" ;
__________________________________________________
Let us examine the left-hand side (the "reactants").
__________________________________________________
                  " <u> ? </u><u /> H₂  +  O₂ " ; 
__________________________________________________
On the left-hand side, we already have: 
__________________________________________________
     1)   " 2  O's " ;   →  one "O₂" = "2 O's" ;  and:
     2)    "2  H's " ;   →  one "H<span>₂" .</span>

Now, we would need:
__________________________________________________
A "<u>total of "4 H's</u>".  Is there any number we could put as a coefficient on the other reactant, which happens to be:  "H₂" ;  to make a <u><em>total of</em></u> "4 H's" ?          

         {Note: There are only these TWO (2) reactants in this chemical equation.}.  

        → The "H₂" ;  as it stands alone, is insufficient—since that would be only                                                                                         "2 H's".
 __________________________________________________
     →  Thus, we can rule out:  "Answer choices: [A] and [D]."  
___________________________________________________
<u>Note</u>:  
→  Choice [A]:  "1" ;  The coefficient, "1";  is generally not (never?) used; and basically would function as the same as:
          →  Choice: [D]:  "<span>no coefficient is needed".
</span>→  <span>Choices [A] & [D]: would leave us with only "2 H's" on the "reactants side" (i.e. "left-hand side of the equation"; and we need FOUR ("4 H's").
__________________________________________________
Since we are given:  "H</span>₂" ; what coefficient could we put in front of this to get:       "4 H's" ?  (4÷2 =2).  So we could put a "2" in front of the "H₂" ; to get: 
    "4 H's".  The coefficient, "2" , corresponds directly with: 
__________________________________________________
                                             → Answer choice:  [B]:  "2" .
_________________________________________________
   { <u>NOTE</u>:  The remaining answer choice, [C], which is, "3" ; is INCORRECT; since 3 "H₂'s" would be "6 H's" ; (since 3 * "2 H's" equal "6 H's") ; which is too many "H's" → We need <u>exactly</u> "4 H's".}.
_________________________________________________
   So, the correctly balanced equation is:

             2 H₂ + O₂ → 2 H₂O  ; 
_________________________________________________
     → The coefficient that goes before the "H₂" ; to make this chemical equation balanced, is:  "2" . 
_________________________________________________
The correct answer is:  [B]:  "2" .  

      → The coefficient that goes before the "H₂" is:  "2" .
_________________________________________________
         Hope this answer—and {lengthy} explanation—is of help!
_________________________________________________
8 0
3 years ago
Read 2 more answers
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