Linear relationships that have different y-intercept and slope of 1/5 is y=1/5 x+25/6.
Given that, the slopes are 1/5, 3/5 and 6/5.
<h3>What is slope of a line?</h3>
The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.
The coordinate points from the given figure are (6, 5), (5, 1) and (4, 3).
Substitute m=1/5 and (x, y)=(6, 5) in y=mx+c, we get
5=1/5 ×6+c
⇒ c=5- 5/6
⇒ c=25/6
Put m=1/5 and c=25/6 in y=mx+c, we get
y=1/5 x+25/6
Substitute m=3/5 and (x, y)=(5, 1) in y=mx+c, we get
1=3/5 ×5+c
⇒ c=-2
Put m=3/5 and c=-2 in y=mx+c, we get
y=3/5 x-2
Substitute m=6/5 and (x, y)=(4, 3) in y=mx+c, we get
3=6/5 ×4+c
⇒ c=3-24/5
⇒ c= -9/5
Put m=6/5 and c= -9/5 in y=mx+c, we get
y=6/5 x-9/5
Therefore, linear relationships that have different y-intercept and slope of 1/5 is y=1/5 x+25/6.
To learn more about the slope of a line visit:
brainly.com/question/14511992.
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