THE AVERAGE RATE CHANGE OF F IS SLOWER THAN THE AVERAGE RATE OF CHANGE OF G OVER INTERVAL [0,2]
1.2x10^4
Step-by-step explanation:
2.
negative exponent means it's a fraction so
4.5x10^-3 is 1/4500 or 0.0045 so
it's a very small number
1.
^4 means means move the decimal 4 spots
12×10^4 = 12,000
3.
^3 means move the decimal 3 spots
3.8 x 10^3 =
3800
4.
7.5x10^3 =
7500
Answer:
x ≤ 3764.72
Step-by-step expl
anation:
The Montanez family cannot use more than 7250.50 gallons, this means that they can use less than or equal to 7250.50 gallons, this tells you which sign to use. The variable x can be used to describe how much water they have left to use and then you add 3,485.78 gallons to x.
x + 3485.78 ≤ 7250.50 This inequality means that the amount of water the family has yet to use added to 3485.78 gallons cannot exceed 7250.50 gallons.
Next, you simplify the inequality using the property of inequalities.
x ≤ 7250.50 - 3485.78
x ≤ 3764.72
Answer:
1/-1
Step-by-step explanation:
y2-y1/x2-x1
8-y2
7-y1
3-x2
4-x1
8-7/3-4
1/-1
Given:
Quadrilateral PQRS
P(o, o), Q(a+c, o), R(2a+c, b), S(a, b)
Find:
whether the diagonals are perpendicular using coordinate geometry
Solution:
If the diagonals are perpendicular, their slopes multiply to give -1.
The slope of PR is
(b-o)/(2a+c-o)
The slope of QS is
(b-o)/(a-(a+c)) = (b-o)/(-c)
The product of these slopes is
(b-o)·(b-o)/((2a+c-o)(-c))
This value will not be -1 except for very specific values of a, b, c, and o.
It cannot be concluded that the diagonals of PQRS are perpendicular based on the given coordinates.