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Feliz [49]
3 years ago
8

In a game of luck, a turn consists of a player rolling 7 six-sided dice and counting how many of the dice

Mathematics
1 answer:
harkovskaia [24]3 years ago
4 0

Answer: Binomial

Step-by-step explanation:

1 / 3

A binomial setting has a set number of trials, and the variable in question is the number of

successes that occur in those trials.

A geometric setting does not have a set number of trials, and the variable in question is the

number of trials it takes to get the first success.

In both settings, the trials are independent and the probability of success remains the same on

each trial.

2/3

In this game, the player rolls 7 dice, and F is the number of dice that show a 5. So the variable is

counting the number of successes

The rolls are independent, and the probability of getting a 5 is the same on each roll,

3/3

F is a binomial variable

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5z^3 - 2z^4 - 9z^2 + z
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Answer:

-z( 2z^3-5z^2+9z-1)

Step-by-step explanation:

Apply exponent rule: a^b+c=a^b*a^c

z^2=zz

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z^4=z^3*z

Factor out common term z:

-z(2z^3-5z^2+9z-1)

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Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
Fed [463]

Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

  • Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171,  Z = (4171 - 3311)/860 = 1  

  • P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

  approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

5 0
3 years ago
What is the distance between point A and point B?
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Answer:

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Step-by-step explanation:

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