One possible model is:

You could place 3 red marble and 1 blue marble in a bag. The probability of drawing a red marble would be 3/4, which is 75%; this means red marbles would be sunny days and blue marbles would be cloudy days.

Each draw out of the bag would represent one day of the week. Draw a marble 7 times, replacing it after each draw. This would represent the weather for the days of the week.

8 0

3 years ago

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Ial

My name is Ann [436]

Answer:

The correct option is 1. Fiona's first step is isolating constant 1.

Step-by-step explanation:

I took it on EDG

6 0

3 years ago

What are the potential solutions to the equation 2ln(x+3)=0

skad [1K]

$2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1$

Expanding the left side gives

$x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0$

which gives two solutions, $x=-4$ and $x=-2$ . But if $x=-4$ , then $\ln(x+3)=\ln(-1)$ , but this number isn't real, so $x=-4$ is an extraneous solution. Meanwhile if $x=-2$ , you get $\ln(-2+3)=\ln1=0$ , so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.

4 0

3 years ago

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512−−−√3= what is the ANSWER HURRY

Tems11 [23]

512 root 3 equals 886.810

4 0

3 years ago