Any of the 11 man can be chosen, and combined with any of the 8 women.
Assume we select man1. The selected committee can be:
(m1,w1), (m1,w2), (m1,w3), (m1,w4), (m1,w5), (m1,w6), (m1,w7), (m1,w8),
so there are 8 committees selections with man1 in them.
we could repeat the same procedure for the remaining 10 men, and get 8 committees where each of them is a member.
so there are 11*8=88 ways of choosing 1 man and 1 woman.
Answer: 88
Hello :
<span>this increasing function F(x)=3x because : the slope 3
is positif</span>
60 / 96 = 25 / q
5 / 8 = 25 / q
5*q = 8 * 25
5q = 200
q = 40
Check:
60 / 96 = 25 / 40
5/8 = 5/8 :)
