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ruslelena [56]
3 years ago
15

Need help I’m stuck

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0
The answer should be B
inside the first parenthesis, 7 on the top and 7 on the bottom cancel each other, so you have (6/5)^2
inside the second parenthesis, 7^0=1, the bottom 5^-3 moves to the top and becomes 5^3, (5^3)=5^9, 5^9 and 5^-9 makes 5^0, which is 1
so all you have left is (6/5)^2, which is 36/25
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U cant even imagine this happening i didnt know free BRAINLEST
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Answer:

Brainliest

Step-by-step explanation:

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Help!! I have exam in 10 minutes
Natalka [10]

Answer:

LHS=(1-sin60)/cos60

=(1-√3÷2)/1÷2

=2(1-√3÷2)

=2-√3

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={1-(1÷√3)}/{1+(1÷√3)}

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={(√3-1)(√3-1)}/{(√3+1)(√3-1)}

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Using a picture, show house six people could share for sandwiches. Then, write an equation and solve.
irinina [24]
Make a rectangle and split it into 6 equal parts.  Example, Joe brought a long ham sandwich split into 6 parts for him and his two friends. If they all want to eat the same amount, how many pieces does each person get?
6 0
3 years ago
What is the equation of the line that is parallel to the line 2x+3y=-8 and passes through the point (2,-2)?
Leya [2.2K]

Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is y=\frac{-2 x}{3}+\frac{-2}{3}

<h3><u>Solution:</u></h3>

Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)

Generic slope intercept form of a line is given by y = mx + c

where "m" = slope of the line and "c" is the y - intercept

Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

\begin{array}{l}{2 x+3 y=-8} \\\\ {=>y=\frac{-2 x-8}{3}} \\\\ {\Rightarrow y=-\frac{2}{3} x-\frac{8}{3}}\end{array}

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

\text {for line } 2 x+3 y=-8, \text { slope } m=-\frac{2}{3}

We know that slopes of parallel lines are always equal

So the slope of line passing through (2, -2) is also m=-\frac{2}{3}

Equation of line passing through (x_1 , y_1) and having slope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=2 \text { and } y_{1}=-2

Substituting the values in equation of line we get

(y-(-2))=-\frac{2}{3}(x-2)

\begin{array}{l}{\Rightarrow y+2=\frac{-2 x+4}{3}} \\\\ {=>3(y+2)=-2 x+4} \\\\ {=>3 y+6=-2 x+4} \\\\ {3 y=-2 x-2}\end{array}

y=\frac{-2 x}{3}+\frac{-2}{3}

Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as y=\frac{-2 x}{3}+\frac{-2}{3}

7 0
4 years ago
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kupik [55]

Answer:

C

hope this helps :-)

7 0
4 years ago
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