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2 answers:
Hope you could understand.
If you have any query, feel free to ask.
Hey there mate :)
My answer is attached as picture. Please check.
<em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>e</em><em>d</em><em> </em><em>b</em><em>y</em><em> </em><em>B</em><em>e</em><em>n</em><em>j</em><em>e</em><em>m</em><em>i</em><em>n</em>
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The first option: 2x^2+2x-4 since there are three terms
Answer:
A = 3
B = 1
C = 2
D = 10
E = 2
F = Not listed
G = 1
Step-by-step explanation:
![\sqrt[3]{270x^5y^7} =\sqrt[3]{27*10x^5y^7}=3xy^2\sqrt[3]{10x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B270x%5E5y%5E7%7D%20%3D%5Csqrt%5B3%5D%7B27%2A10x%5E5y%5E7%7D%3D3xy%5E2%5Csqrt%5B3%5D%7B10x%5E2y%7D)
349*.15=52.35
you save 52.35
Answer:
-1
Explanation:
Let the number be x.
Then the equation will be:
3(x+18) = 51
=> 3x + 54 = 51
=> 3x = 51 - 54
=> 3x = -3
=> x = -3/3
=> x = -1
So, the number you thought of is -1.
