X is a normally distributed random variable with a mean of 8 and a standard deviation of 4. The probability that x is between 1.
48 and 15. 56 is.
1 answer:
Answer:
P(1.48<X<15.56) ≈ 0.919 ≈ 91.9%
Step-by-step explanation:
2nd+DISTR --> normalcdf
P(1.48<X<15.56) = normalcdf(1.48,15.56,8,4) ≈ 0.919
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