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Maksim231197 [3]

2 years ago

5

X is a normally distributed random variable with a mean of 8 and a standard deviation of 4. The probability that x is between 1.

48 and 15. 56 is.

1 answer:

Natalka [10]2 years ago

7 0

Answer:

P(1.48<X<15.56) ≈ 0.919 ≈ 91.9%

Step-by-step explanation:

2nd+DISTR --> normalcdf

P(1.48<X<15.56) = normalcdf(1.48,15.56,8,4) ≈ 0.919

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