Answer:
The correct option is second one i.e 24 units.
Therefore the height of the triangle is
Step-by-step explanation:
Given:
An equilateral triangle has all sides equal.
ΔMNO is an Equilateral Triangle with sides measuring,
NR is perpendicular bisector to MO such that
.NR ⊥ Bisector.
To Find:
Height of the triangle = NR = ?
Solution :
Now we have a right angled triangle NRM at ∠R =90°,
So by applying Pythagoras theorem we get
Substituting the values we get
Therefore the height of the triangle is
As stated the area of the circle is 85π ft2. The area of the sector BAC is a portion of this full circle area. the sector is made of 2 radii and arc that has rotated by 36°.
the magnitude of the central angle in the circle is 360°
Area for 360° central angle - 85π ft2
then the area for 1° = 85π ft2/360°
the area of 36° sector = 85π ft2/360° x 36°
= 8.5π ft2
C 75.00- 1/3 were cookies which is 150 cookies. 150x0.50=75.00
Add apples to pears, getting 63, then find the square root which should be 7.937
Answer:
See below.
Step-by-step explanation:
So we started off with the equation:
And we subtracted x from both sides to acquire:
Now, this is essentially slope-intercept form. Recall that the slope-intercept form is:
Where m is the slope and b is the y-intercept.
If we rearrange our equation:
And put some parentheses:
We can see that this is indeed slope-intercept form.
And we can see that m is -1 and b is 2.
In other words, the slope is -1 and the y-intercept is 2.
