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siniylev [52]
2 years ago
12

Write an algebra expression

Mathematics
1 answer:
maksim [4K]2 years ago
4 0
1(2+3)4•5(6-7)+8+9-10 lol
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I really need help.​
Harman [31]

Answer:

an equivalent fraction for 1/2 is 5/10 an equivalent fraction for 1/3 is 3/9 hope this helps

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Create an expression that you would use to solve the problem below.
masya89 [10]

The tool was used for 28 minutes

Step-by-step explanation:

We will use simple division to calculate the number for minutes for which the tool was rented

Given

Cost per minute = $0.65

Total cost = $18.20

Let x be the number of minutes

So,

x = \frac{Total\ cost}{Cost\ per\ minute}\\= \frac{18.20}{0.65}\\=28\  minutes

The tool was used for 28 minutes

Keywords: Division, Linear equation

Learn more about division at:

  • brainly.com/question/12973601
  • brainly.com/question/13063819

#LearnwithBrainly

7 0
3 years ago
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5x + 8 − 3x = −10<br><br> x = −9<br> x = −1<br> x = 1<br> x = 9
zvonat [6]

Answer:

-9

Step-by-step explanation:

7 0
4 years ago
What is the slope of (-2, 2) and (3, 4)?
Pepsi [2]

Answer:

2/5

Step-by-step explanation:

m = (2-4)/(-2-3) = 2/5

5 0
2 years ago
The chief chemist for a major oil and gasoline production company claims that the regular unleaded gasoline produced by the comp
Svetradugi [14.3K]

Answer:

The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = 0.00621

Step-by-step explanation:

This is a normal distribution problem

The mean of the sample = The population mean

μₓ = μ = 4 ounces

But the standard deviation of the sample is related to the standard deviation of the population through the relation

σₓ = σ/√n

where n = Sample size = 100

σₓ = 1.2/√100

σₓ = 0.12

The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3)

To do this, we first normalize/standardize the 4.3 ounces

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (4.3 - 4)/0.12 = 2.5

To determine the probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = P(z > 2.5)

We'll use data from the normal probability table for these probabilities

P(x > 4.3) = P(z > 2.5) = 1 - P(z ≤ 2.5) = 1 - 0.99379 = 0.00621

5 0
4 years ago
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