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2 years ago

When pointing A(-6. - 12) is reflected over the y-axis to get point B, what are the

Mathematics

1 answer:

Fudgin [204]2 years ago

4 0

Answer:

Step-by-step explanation:

under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

A (- 6, - 12 ) → B (6, - 12 )

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14+16+11+2+6+6+15+2+11<br> And round to the nearest tenth

Liula [17]

Answer:

Step-by-step explanation:

Add the numbers together

5 0

3 years ago

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Between which two numbers is √8 located on a number line?

Lady_Fox [76]

Answer:

√8 is between 2 and 3.

Step-by-step explanation:

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2 years ago

5x=4y make x the subject

oee [108]

Answer:

$x = \frac{4y}{5}$

Step-by-step explanation:

$5x = 4y\\\rule{150}{0.5}\\\frac{5x=4y}{5}\\\\\boxed{x = \frac{4y}{5}}$

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3 years ago

There are about 1.5 grams of fat in 1 tablespoon of hummus. How many grams of fat are in 2 1/2 cups of hummus? ( Note: 16. Table

grin007 [14]

2 and 1/2=2.5cups
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1.5g=1tbs
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3 years ago

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Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0

3 years ago