To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).
Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.
The power rule for derivatives is ![\frac{d}{dx} [x^{n} ] =nx^{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bx%5E%7Bn%7D%20%5D%20%3Dnx%5E%7Bn-1%7D)
. In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.
f'(x) = 
(2x⁴)
f'(x) = 2(4)x³
f'(x) = 8x³
Now, to find f'(3), plug 3 into your derivative.
f'(3) = 8(3)³
f'(3) = 216
<h3>Answer:</h3>
f'(3) = 216
2:3
6 ÷ 2 = $3 (cost of 1 pack of butter cookies)
3 x 3 = 9 (cost of 3 packs of butter cookies)
17 - 9 = 8 (cost of 4 packs of chocolate cookies)
8 ÷ 4 = 2 (cost of one pack of chocolate cookies)
Z = 3 (This equation is a given)
z(y) = 12 ( This equation is also given)
3y = 12 (as z = 3, plug 3 into z)
3y/3 = 12/3 (isolate the y by dividing 3 to both sides)
* you divide 3 to both sides because of the equal sign. What you do to one side you do to the other
y = 4 (answer for y)
y + 5 (what you are solving for)
(4) + 5 = 9 (As y = 4, plug in 4 for y in this equation)
y + 5 = 9 (4 + 5 = 9, or addition property)
9 is your answer
hope this helps
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