Divide 102 by 300 to get .34 and multiply it by 100% to get 34%
Answer:
14.69% probability that defect length is at most 20 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What is the probability that defect length is at most 20 mm
This is the pvalue of Z when X = 20. So



has a pvalue of 0.1469
14.69% probability that defect length is at most 20 mm
Answer:
38%
Step-by-step explanation:
$600 is 100%
$60 is 10%
$6 is 1%
3 60s go into 228 with 48 still left.
6 times 8 is 48.
So its 38%.
Answer:
y=x+2
Step-by-step explanation:
Given, m = 1
Eqn of st line is y = mx + c
y = 1*x + c
y= x + c ........eqn (i)
since, the line passes through the point (4,2)
4 = 2 + c
c = 4 - 2
c = 2
Now, Putting the value of c = 2 in eqn (i)
y = x + 2 is req eqn of line
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