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2 years ago

Order these weights from lightest to heaviest.

Mathematics

1 answer:

Inga [223]2 years ago

8 0

-Anwser
2 kilograms =
4.409 pounds

500 grams =
1.102 pounds

5 pounds =
80 ounces

15 ounces =
0.938 pounds

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Please help me on this

kenny6666 [7]

Answer19/40=x/3.6

By cross multiplication

19*3.6=40*x

68.4 =40x

x=68.4/40

x=1.71

7 0

3 years ago

Read 2 more answers

An equation is shown. What is the value for x that makes the equation true? 8 x = 35

Studentka2010 [4]

Answer:

x=27

Step-by-step explanation:

8x=35

-8 -8

x=27

8 0

3 years ago

Which of the following is a solution to this inequality? y greater than three fifths times x minus 2 (5, 0) (0, −2) (1, 1) (−5,

storchak [24]

Answer:

(1,1)

Step-by-step explanation:

we have

$y > \frac{3}{5}x-2$

we know that

If a ordered pair is a solution of the inequality, then the ordered pair must satisfy the inequality

<u><em>Verify each ordered pair</em></u>

case A) we have

(5,0)

Substitute the value of x and y in the inequality

$0 > \frac{3}{5}(5)-2$

$0 > 1$ ----> is not true

therefore

The ordered pair is not solution to the inequality

case B) we have

(0,-2)

Substitute the value of x and y in the inequality

$-2 > \frac{3}{5}(0)-2$

$-2 > -2$ ----> is not true

therefore

The ordered pair is not solution to the inequality

case C) we have

(1,1)

Substitute the value of x and y in the inequality

$1 > \frac{3}{5}(1)-2$

$1 > -\frac{7}{5}$ ----> is true

therefore

The ordered pair is a solution to the inequality

case D) we have

(-5,-6)

Substitute the value of x and y in the inequality

$-6 > \frac{3}{5}(-5)-2$

$-6 > -5$ ----> is not true

therefore

The ordered pair is not solution to the inequality

7 0

3 years ago

Read 2 more answers

A go-cart racetrack has 100-meter straightaways and semicircular ends with diameters of 40 meters. Calculate the average speed i

emmainna [20.7K]

Answer:

Average speed of go cart is 217.07 meters per minute.

Step-by-step explanation:

We are given the following in the question:

Length of straightway racetrack = 100 m

Diameter of semicircular end = 40 m

Radius =

$r = \dfrac{d}{2} = \dfrac{40}{2} = 20\text{ m}$

Perimeter of racetrack =

Perimeter of semicircle + 2(Length of straightway) + Perimeter of semicircle

$=\pi r + 2(100) + \pi r\\=2\pi r + 2(200)\\=(2\times 3.14\times 20) + 200\\=325.6\text{ m}$

Speed =

$s = \dfrac{\text{Distance}}{\text{Time}}\\\\s = \dfrac{4\times \text{Perimeter of track}}{6}\\\\s = \dfrac{4\times 325.6}{6}\\\\s = 217.06\text{ meter per minute}$

Thus, average speed of go cart is 217.07 meters per minute.

4 0

3 years ago

WILL GIVE BRAINLIEST!!!!!! AND 40 POINTS

olga2289 [7]

Answer:

360°

Step-by-step explanation:

xjjdjdjdjedjejdjej

8 0

3 years ago