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kotegsom [21]
2 years ago
11

What is the area of the circle?​

Mathematics
2 answers:
Gelneren [198K]2 years ago
7 0

Answer:

For a circle.

Step-by-step explanation:

A=πr^2

BartSMP [9]2 years ago
7 0

Answer:

A=\pi r^{2}

Step-by-step explanation:

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A soccer league has 160 players. Of those players 60% are boys. How many boys are in the soccer league?
yan [13]

Answer:

There are 96 boys in the soccer league.

Step-by-step explanation:

You multiply 160 by 60%, which is also 160*.6.

160*.6=96

8 0
3 years ago
Read 2 more answers
In 2004 a football team scored 27, 19, 12, 20, 20, 26, 23, 29, 20, 17, 61, 30, and 31 points in their first 13 games. Find the m
miv72 [106K]
After adding all the numbers together then dividing the sum by 13 I got 25.7 rounded to 26
8 0
3 years ago
Bhavik bought 333 liters of milk and 555 loaves of bread for a total of \$11$11dollar sign, 11. A month later, he bought 444 lit
AnnZ [28]

Let the price of 1 litre of milk be  x$

Let the price of 1 loaf of bread be y$

According to the problem

333x + 555y =11

444x+444y=10

On subtracting the two,

We get

(333x+555y=11) * 444

(444x+444y= 10) * 333

(-)     (-)         (-)

147852x + 246420y =4884

147852x + 147852y = 3330

(-)            (-)                  (-)

------------------------------                   

 98568y = 1554     

           y = 1554/98568     

              = 0.0157$          

                 =0.02$    

Price of 1 loaf of bread= 2 cents    

On putting the value of y 

333x + 555*0.0157 = 11333x  + 8.7135 = 11333x = 2.2865x = 2.2865/333x = 0.00068$   = 0.01$

Price of 1 litre of milk = 1 cent

1.5


6 0
3 years ago
38. Evaluate f (3x +4y)dx + (2x --3y)dy where C, a circle of radius two with center at the origin of the xy
lina2011 [118]

It looks like the integral is

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy

where <em>C</em> is the circle of radius 2 centered at the origin.

You can compute the line integral directly by parameterizing <em>C</em>. Let <em>x</em> = 2 cos(<em>t</em> ) and <em>y</em> = 2 sin(<em>t</em> ), with 0 ≤ <em>t</em> ≤ 2<em>π</em>. Then

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \int_0^{2\pi} \left((3x(t)+4y(t))\dfrac{\mathrm dx}{\mathrm dt} + (2x(t)-3y(t))\frac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^{2\pi} \big((6\cos(t)+8\sin(t))(-2\sin(t)) + (4\cos(t)-6\sin(t))(2\cos(t))\big)\,\mathrm dt \\\\ = \int_0^{2\pi} (12\cos^2(t)-12\sin^2(t)-24\cos(t)\sin(t)-4)\,\mathrm dt \\\\ = 4 \int_0^{2\pi} (3\cos(2t)-3\sin(2t)-1)\,\mathrm dt = \boxed{-8\pi}

Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on <em>C</em> nor in the region bounded by <em>C</em>, so

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \iint_D\frac{\partial(2x-3y)}{\partial x}-\frac{\partial(3x+4y)}{\partial y}\,\mathrm dx\,\mathrm dy = -2\iint_D\mathrm dx\,\mathrm dy

where <em>D</em> is the interior of <em>C</em>, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: -2\times \pi\times2^2 = -8\pi.

3 0
2 years ago
The ratio in simplest form
Hoochie [10]
It’s already in it’s simplest form!
8 0
3 years ago
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