Answer:
Let P(x) = x is in the correct place
Let Q(x) = x is in the excellent place
R(x) denotes the tool
Explanation:
a) Something is not in the correct place.
P(x) is that x is in the correct place so negation of ¬P(x) will represent x is not in the correct place. ∃x is an existential quantifier used to represent "for some" and depicts something in the given statement. This statement can be translated into logical expression as follows:
∃x¬P(x)
b) All tools are in the correct place and are in excellent condition.
R(x) represents the tool, P(x) represents x is in correct place and Q(x) shows x is in excellent place. ∀ is used to show that "all" tools and ∧ is used here because tools are in correct place AND are in excellent condition so it depicts both P(x) and Q(x). This statement can be translated into logical expression as follows:
∀ x ( R(x) → (P(x) ∧ Q(x))
c) Everything is in the correct place and in excellent condition.
Here P(x) represents correct place and Q(x) represents excellent condition ∀ represent all and here everything. ∧ means that both the P(x) and Q(x) exist. This statement can be translated into logical expression as follows:
∀ x (P(x) ∧ Q(x)
1.
#include <iostream>#include <string>
using namespace std;
int main(){ string chars; // This is where we will put our @ signs and print them for(int x=0;x < 5; x++){
chars = chars + '@'; // This will concatenate an @ sign at the end of the variable cout << chars << "\n"; }}
2.
#include <iostream>#include <string>
using namespace std;
int main(){ string name; // Our variable to store the name cout << "What is your name? \n"; // Asks the user for their name cin >> name; cout << "\nWell, hello " << name << "!";}
3.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; // Asks for a number cin >> number; cout << "You entered " << number << "%!";}
4.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; cin >> number;
int check = number % 2; // The modulo operator (the percent sign) gets the remainder of the quotient if (check == 0) { cout << number << " is even!"; // If the remainder is 0 then it prints out "x is even" } else { cout << number << " is odd!"; // If the remainder is not 0 then it prints out "x is odd" }}
5.
#include <iostream>#include <string>
using namespace std;
int main(){ float r; // Our variable cout << "Enter a radius\n"; cin >> r; if (r < 0){ cout << "Lol. No."; // If the radius is less than zero print out that message } float circumference=2*3.14*r; float area=r*r*3.14; cout << "\n\n Circumference of circle: " << circumference; cout << "\n Area of circle: " << area;}
Answer: it does – or perhaps appears to do – in the world.
Explanation:
sorry if am not right have a nice day lol
You would click the right button to a shortcuts
