Not sure what quizScore1-5 is, but here it is. Also, I'm not entirely sure what language you're working with here, but null can't be returned as an integer. If it were a string, for example, it'd be possible as string is an object reference type.
public int getData(int dataNumber)
{
if (dataNumber == 1)
return quizScore1;
else if (dataNumber == 2)
return quizScore2;
else if (dataNumber == 3)
return quizScore3;
else if (dataNumber == 4)
return quizScore4;
else if (dataNumber == 5)
return quizScore5;
else
return 0;
}
Answer:
c. Messages flowing to the client typically use a source TCP port number of 80.
d. Messages flowing to the server typically use TCP.
Explanation:
When fred open the web browser and start a connection to the www.certskills.com website.Two things happens from the mentioned things
1.Messages that are going to the server are use TCP(Transmission Control Protocol).
2.Message goes to the client uses port number 80 that is of TCP used for transferring web pages.
Because the port number 80 is reserved for the HTTP used for transferring web pages that uses TCP protocol.
If on a computer, if thee computer says they put it in the recycling bin, the go to the recycling bin and right click and delete. If a paper, throw away. If other, do what your body desires to do.<span />
Answer:
Explanation:
We start from the bottom-most and rightmost internal node of min Heap and then heapify all internal modes in the bottom-up way to build the Max heap.
To build a heap, the following algorithm is implemented for any input array.
BUILD-HEAP(A)
heapsize := size(A)
for i := floor(heapsize/2) downto 1
do HEAPIFY(A, i)
end for
Convert the given array of elements into an almost complete binary tree.
Ensure that the tree is a max heap.
Check that every non-leaf node contains a greater or equal value element than its child nodes.
If there exists any node that does not satisfy the ordering property of max heap, swap the elements.
Start checking from a non-leaf node with the highest index (bottom to top and right to left).