Question

Unit 8: Right Triangles & Trigonometry

Answer 1

Answer:

See below

Step-by-step explanation:

Problem 6

$tan\theta=\frac{opposite}{adjacent}\\ \\tan58^\circ=\frac{22}{x}\\ \\xtan58^\circ=22\\\\x=\frac{22}{tan58^\circ}\\\\x\approx13.7$

Problem 7

$tan\theta=\frac{opposite}{adjacent}\\ \\tan51^\circ=\frac{x}{15}\\ \\15tan51^\circ=x\\\\x\approx18.5$

Problem 8

$cos\theta=\frac{adjacent}{hypotenuse}\\\\cos37^\circ=\frac{48}{x}\\ \\xcos37^\circ=48\\\\x=\frac{48}{cos37^\circ}\\ \\x=60.1$

Problem 9

$sin\theta=\frac{opposite}{hypotenuse}\\ \\sin24^\circ=\frac{x}{9}\\ \\9sin24^\circ=x\\\\x\approx3.7$

Remember your trigonometry formulas and fix the problems you already did. They look wrong.