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Vilka [71]
3 years ago
9

Y + x = 3 y = 1.5x + 1 find x and y

Mathematics
2 answers:
aliya0001 [1]3 years ago
6 0

x=0.8, y=2.2

The image has the work shown

Hope this helps

Licemer1 [7]3 years ago
6 0

Answer:

y + x = 3 \\  \\ y =  - x + 3 \\  \\  - x + 3 = 0 \\  \\  - x =  - 3 \\  \\ x = 3 \\  \\ y = 1.5x + 1 \\  \\ y = 1.5 \times 3 + 1 \\  \\ y = 4.5 + 1 \\  \\ y = 5.5

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MAXImum [283]

Answer:

x=3 and N is the mid-point.

Okay, so if N is the mid-point.

E D=15

E N=4 x -1

N D=4+ 2 x

6 x -3=15

Now get the 6 x by itself, so move the 3 over

So it would be: 6 x =18

So that would be 6 divided by 6 is x and then 18 divided by 6 equals 3

So, X equals 3

6 0
1 year ago
a video game club has 42 members the number of high school members is six less than twice the number of middle school memebers w
jonny [76]

Answer:

26

Step-by-step explanation:

h represents highschool members

m represents middle school members

42 = h+m

h = 2m-6

Substitute h for 2m-6 in first equation:

42 = (2m-6)+m

Solve for m:

42 =3m-6

48 = 3m

m = 16

Subsitute 16 for m in second equation:

h = 2(16)-6

Solve for h:

h = 32-6

h = 26

5 0
3 years ago
The temperature is -27° Celsius. Give the absolute value and explain what it means.
jenyasd209 [6]
I do not know I m sorry
7 0
3 years ago
Read 2 more answers
John can buy a 24 oz bottle of ketchup for $2.19 or a 36 oz bottle for $3.79. Which is the better buy
soldier1979 [14.2K]

Answer:

24 oz bottle of ketchup for $2.19 is the better buy

Step-by-step explanation:

24/2.19=10.96

36/3.79=9.50

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8 0
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each side of a small square gym is 17 meters long. a square classroom has half the area of the gym. how long is each side of the
Semmy [17]

If the gym is a square with 17 meters sides, its area is given (as any other square) by the square of the side:

A_{gym} = 17^2 = 289 \text{ m}^2

So, the area of the classroom is

A_{class} = \dfrac{289}{2}=144.5 \text{ m}^2

We can deduce the side of the classroom only assuming that it is a square as well: if this is the case, the side of a square with given area is the square root of the area, so we have

s_{class} = \sqrt{144.5} \approx 12.02 \text{ m}

5 0
3 years ago
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