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Taya2010 [7]
2 years ago
5

Please help i’ll give you brainlieest

Mathematics
2 answers:
ivanzaharov [21]2 years ago
9 0

Answer:

Answer is: (9)

Step-by-step explanation:

105+(8v+3)=180

(8v+3)=75

8v=72

v=9

OLEGan [10]2 years ago
4 0
105 + 105 = 210
opposite angels are the same
(8v + 3 ) + ( 8v+ 3)= 16v + 6
210 + 16v + 6 = 216 + 16 v
216 + 16v = 360
360 - 216 = 144
16 v = 144
v = 9
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Answer:D. x^2+7

Step-by-step explanation:

If f(x) = 2x² +5 and g(x)=x2-2, find (f-g)(x).A. x^2+3B. 3x^2+3C. 3x^2+7D. x^2+7

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2 years ago
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guapka [62]

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3 years ago
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

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3 years ago
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\nabla_{\mathbf u}f=\nabla f\cdot\dfrac{\mathbf u}{\|\mathbf u\|}

With f(x,y,z)=xyz, we get

\nabla f=(yz,xz,xy)

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What is 17x greater than -17?
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