Answer:
Round trip times required = log2N
Explanation:
The round-trip times required before TCP can send N segments using a slow start is log2N. we can arrive at this by looking at the mode of operation of TCP which is at the 1st time of using a TCP it starts the congestion window as 1 then it sends an initial segment. When the acknowledgement of the initial segment arrives, TCP increases the congestion window to 2 and then sends 2 segments, When the 2 acknowledgements of the segments sent out arrives, they each increase the congestion window by one, thereby increasing the congestion window to 4 . therefore it takes log2N round trips before TCP can send N segments
Answer:
Inner class in Java is basically a class in a class, i.e. a member of another class.
There are 4 types of inner classes in Java.
a) Nested Inner class
b) Method local Inner class
c) Anonymous Inner class
d) Static nested class
It is true that in the array implementation of a queue, the pop operation is most efficient if the front of the queue is fixed at index position. The correct option is a.
<h3>What is pop operation? </h3>
The removal of an element is referred to as a pop operation. Again, because we only have access to the element at the top of the stack, we can only remove one element. We simply take the top of the stack off.
A push operation decrements the pointer before copying data to the stack; a pop operation copies data from the stack before incrementing the pointer.
The pop operation in an array implementation of a queue is most efficient if the queue's front is fixed at index position.
Thus, the correct option is a.
For more details regarding pop operation, visit:
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