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Mars2501 [29]
2 years ago
11

(5+6i) divided by (2-7i)

Mathematics
1 answer:
ss7ja [257]2 years ago
6 0

Answer:

i = 7

Step-by-step explanation:

you combine like terms divide and then u get 1i = 7 when u divide it equals 7 this how i got i = 7

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Whats does pemdas mean
Bumek [7]
Its a common technique for remembering the order of operations. The abbreviation pemdas is turned into the phrase "Please excuse my Dear Aunt Sally". It stands for "Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction.
8 0
3 years ago
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Can some help me out with this EXTRA POINTS!!
Butoxors [25]

Answer: ≈ 185.73009

Step-by-step explanation:

area of square: length^{2}

area of circle: \frac{radius^{2} * \pi }{y}

length: 15

radius = diameter/2

radius: 5

area of square - area of circle =  area between square and circle:

15^{2} - \frac{5^{2} * \pi }{2} = 225 - \frac{25\pi}{2} ≈ 185.73009

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8 0
2 years ago
an integer is one more than four times another. if the product of two integers is 39, then find the integers
Sholpan [36]
Sorry if its illegible, you can ask if its not clear

8 0
3 years ago
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In a 30-60-90 triangle, the length of the long leg is 8. Find the length of the hypotenuse.
fiasKO [112]

Answer:

Step-by-step explanation:

In a 30-60-90 triangle, the ratio of the lengths of the angles' opposite sides are <em>1-√3-2</em>.

If the long leg is 8, then the short one is 8/√3, or <em>8√3/3</em>.

Therefore, the hypotenuse, which is <em>double the short leg</em>, is 16√3/3.

5 0
4 years ago
please help me to solve this word problems leading to quadratic equation: A girl is 6 years younger than her brother. the produc
vova2212 [387]

Answer:

Brother is 70.5 and sister is 64.5

Step-by-step explanation:

you will need to set up a simple equation and give out variables.

Girls age = 6-x

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the you will take those 2 and add them and place them equal to 135:

6-x+x=135

6-2x+6=135+6

The 6 cancels out

2x=141

2x/2=141/2

x=70.5

The brother's age would be 70.5 then and the girl's would be 64.5

5 0
3 years ago
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